12 x 12 x 12
explanation: 12 to the 3rd power is simply just 12 times itself 3 times.
It would be C) 5y = -4x -15
So we have v(w) = 2w - 1
Now we make the following change: w ---> w +3.
So we change every "w" into a "w+3" as follows:
v(w) = 2w - 1 --------> v(w+3) = 2*(w+3) - 1
Let's solve this.
2*(w+3) - 1
2*w + 2*3 - 1
2w + 6 - 1
2w + 5
So
v(w+3) = 2w + 5
F(x) = <span>x^2+3x+8
now, the pending of the tangent line is d/dx f(x)
f'(x) = 2x + 3
now, we need know when the pending is increasing.
so
</span>2x + 3> 0
solving
x>-3/2
The interval over which the function f(x)= x^2+3x+8 is <span>increasing is (-3/2,+</span>∞<span>)</span><span>
</span>
Answer:
-2c^2+4c
Step-by-step explanation:
4c^2+6c-6c^2-2c
combine like terms
4c^2-6c^2= -2c^2 and 6c-2c=4c
so
-2c^2+4c is the simplest form and the answer
