Hello:
<span>an = 2an-1 + 5, where a1 = 5
n =2 a2 = 2a1 +5 = 2(5)+5 = 15
</span>n =3 a3 = 2a2 +5 = 2(15)+5 = 35
n =4 a4 = 2a3 +5 = 235)+5 = 75
answer :
<span>B)
5, 15, 35, 75, ...</span>
<h2>
Automobile must travel at 96 mph to pass the truck in 4 seconds.</h2>
Step-by-step explanation:
Length of automobile = 16 feet = 4.88 m
Length of truck = 28 feet = 8.53 m
Speed of truck = 30 mph = 48 km/h = 13.33 m/s
Time in which automobile to pass truck = 4 s
Distance traveled by truck in 4 seconds = 4 x 13.33 = 53.33 m
Distance which need to cover by automobile in 4 seconds to pass truck is the sum of length of automobile, length of truck and distance traveled by truck in 4 seconds.
Distance which need to cover by automobile in 4 seconds = 4.88 + 8.53 + 53.33
Distance which need to cover by automobile in 4 seconds = 66.74 m
Distance = Speed x Time
66.74 = Speed x 4
Speed = 16.69 m/s = 60 km/h = 96 mph
Automobile must travel at 96 mph to pass the truck in 4 seconds.
The answer is the third option which is AEF and FED, AEG and CEG
Answer:
x+17
Step-by-step explanation:
x + 17 is the answer
Step-by-step explanation:
4(a-3)=22
a-3=4-22
a-3=18
a=18+3
a=21
5(x-6)=65
x-6=65-5
x-6=60
×=60+6
x=66
hope it will help u...............
