Question

Find the distance between the two points shown in the coordinate plane below to the nearest hundredth.

Answer 1

Answer:

7.81

Step-by-step explanation:

we have the points: (-2, -2) and (3, 4)

where i will call $x_{1}=-2, y_{1}=-2,x_{2}=3,y_{2}=4$

We can find the distance using the Pythagorean theorem, considering that the distance in x between the points is: $d_{x}=$ $x_{2}-x_{1}=3-(-2)=3+2=5$

and the distance in y  between the points is: $d_{y}=$$y_{2}-y_{1}=4-(-2)=4+2=6$

and using the Pythagorean theorem

$d=\sqrt{d_{x}^2 +d_{y}^2}$

$d=\sqrt{5^2+6^2}=\sqrt{25+36}=\sqrt{61} =7.81$

the distance between the two points ia 7.81

Answer 2

Answer:

7.81

Step-by-step explanation:

= √(5^2 + 6^2)

= √(25 + 36)

= √61

= 7.81