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Katarina [22]
3 years ago
11

A technician is talking to end users about the specifications for an upgraded application server. The users of the application r

eport that there cannot be any unscheduled downtime or data loss. Additionally, they would like the performance of the application to improve over the previous server in any way possible. The previous server running RAID 5. Which of the following RAID solutions should be implemented in this scenario?
Computers and Technology
1 answer:
Anarel [89]3 years ago
4 0

Answer:

According to the requirements of users of the system, RAID 10 is more suitable option.

Explanation:

As mentioned previous server is running RAID 5, Which takes a lot of time to manage parity while reading or writing data.

On the other end RAID 10 is the combination of RAID 1 and RAID 0, It has the the features of both system.

According to the users requirement, unscheduled downtime or data loss can cannot be tolerated. So RAID 10 has the ability to access the data from multiple disks. If one disk i down, required data can be gathered from other disks.

It creates multiple duplicates of data, so risk to lose data has also been reduced.

<em>In both aspects, RAID 10 is better than RAID 5, so he choose RAID 10 for up gradation.</em>

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2. An evil twin attack that broadcasts a legitimate SSID for an unauthorized network is an example of what category of threat? A
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A. Spoofing

Explanation:

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7 0
3 years ago
Write a method called all Less that accepts two arrays of integers and returns true if each element in the first array is less t
GaryK [48]

Answer:

The program to this question can be given as:

Program:

#include<iostream> //header file

using namespace std; //using name space

bool allLess (int arr1[], int arr2[]) //defining method allLess  

{

int a,b; //define variable

a=  *(&arr1 + 1) - arr1; //hold length of arr1

b=  *(&arr2 + 1) - arr2; //hold length of arr2

if(a!=b) //checking condition  

{

return 1; //return value

}

for(int i=0; i<a; i++) //loop

{

if( arr1[i]>=arr2[i]) //checking condition

{

return 1; //return value

}

}

return 0; //return value

}

int main() //define main method.

{

   int arr1[]={1,2,3,4,5}; //define array arr1 and assign value.

   int arr2[]={4,5,6,7,8}; //define array arr2 and assign value.

   cout<< allLess(arr1,arr2); //function calling

   return 0;

}

Output:

1

Explanation:

The Explanation of the C++ language program can be given as follows:

  • In the above program firstly we include the header file. Then a method is defined that is "allLess" this method accepts two arrays that are "arr1 and arr2". This function returns a boolean value that is true or false.
  • Inside a function, we define a conditional statement and a loop in the if block we check the length of the arr1 array variable is not equal to arr2 array length. if this condition is true it will return false.
  • In the loop, we define another if block in this block we check that if arr1 array elements are grater then equal to arr2 array element if this condition is true it will return false. At the end of both if block and loop the function will return a value that is "true".
  • In the main method, we define two arrays and pass to the function and use (cout function) for print return value.
8 0
3 years ago
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