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3 years ago

14

Please help ill give 20 points

1 answer:

anastassius [24]3 years ago

6 0

The hypotenuse is 16 and the longer leg is 8√3

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$40,768 per year what is the weekly gross earnings

nevsk [136]

($40768/y)(y/52w)=$784/week

Seven hundred and eighty-four dollars per week.

5 0

3 years ago

Read 2 more answers

Three vertices of a rectangle are (–2, 1), (–2, –3), and (4, –3)

Tpy6a [65]

The answer is C
it's easier if you graph it
we know that the x of the unknown vertice is 4, because this is a rectangle and that vertices has to be on the same x line as the point below.
y of the unknown vertice has to be 1 because the vertice to the left needs to be on the same y line as the unknown vertice

6 0

3 years ago

Last year, Keiko had $20,000 to invest. She invested some of it in an account that paid %7 simple interest per year, and she inv

erma4kov [3.2K]

Answer:

$P_2 = \$6,000\\P_1 = \$14,000$

Step-by-step explanation:

The formula of simple interest is:

$I = P_0rt$

Where I is the interest earned after t years

r is the interest rate

$P_0$ is the initial amount

We know that the investment was $20,000 in two accounts

_______________________________________________

<u><em>For the first account</em></u> r = 0.07 per year.

Then the formula is:

$I_1 = P_1r_1t$

Where

$P_1$ is the initial amount in account 1 at a rate $r_1$ during t = 1 year

$I_1 = P_1(0.07)(1)\\\\I_1 = 0.07P_1$

<u><em>For the second account </em></u>r = 0.05 per year.

Then the formula is:

$I_2 = P_2r_2t$

Where

$P_2$ is the initial amount in account 2 at a rate $r_2$ during t = 1 year

Then

$I_2 = P_2(0.05)(1)\\\\I_2 = 0.05P_2$

We know that the final profit was I $1,280.

So

$I = I_1 + I_2=1,280$

Substituting the values $I_1$ , $I_2$ and I we have:

$1,280 = 0.07P_1 + 0.05P_2$

As the total amount that was invested was $20,000 then

$P_0 = P_1 + P_2 = 20,000$

Then we multiply the second equation by -0.07 and add it to the first equation:

$0.07P_1 + 0.05P_2 = 1.280\\.\ \ \ \ \ \ \ \ +\\-0.07P_1 -0.07P_2 = -1400\\-------------$

$-0.02P_2 = -120\\\\P_2 = 6,000$

Then $P_1 = 14,000$

4 0

3 years ago

Please help me with 1,2,3,4 and show me how you get it the answers

Dafna11 [192]

Answer:

Step-by-step explanation:

Use the formula of distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ ,

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

1. Distance between A(3, 4) and B(8, 12),

AB = $\sqrt{(8-3)^2+(12-4)^2}$

AB = $\sqrt{25+64}$

= $\sqrt{89}$

≈ 9.43

2. Distance between C(-2, 10) and D(3, -2),

CD = $\sqrt{(3+2)^2+(-2-10)^2}$

= $\sqrt{25+144}$

= $\sqrt{169}$

= 13.00

3. Distance between X(20, 4) and Y(17, 0),

XY = $\sqrt{(20-17)^2+(4-0)^2}$

= $\sqrt{3^2+4^2}$

= $\sqrt{25}$

= 5.00

4. Distance between E(2, -1) and M(6, 9),

EM = $\sqrt{(2-6)^2+(-1-9)^2}$

= $\sqrt{16+100}$

= $\sqrt{116}$

= 10.77

8 0

3 years ago

Will mark brainliest

nexus9112 [7]

Answer: y = (-4/9)x2 + (16/9)x + (47/9)

Step-by-step explanation:

f(x) = a(x - h)2 + k, where the vertex is (h,k) = (2,7) while passing through the point (x,y) = (-1,3). We must plug everything in to solve for a first. Then,

3 = a(-1 - 2)2 + 7

3 = a(-3)2 + 7................Subtract 7 to both sides such that

-4 = 9a...............Then divide 9 such that

a = (-4/9)

Now we plug a into the equation with the vertex to create the parabolic function such that

y = (-4/9)(x - 2)2 + 7 ..............Then FOIL the (x-2)2 such that

y = (-4/9)(x2 - 4x + 4) + 7..............Then distribute the (-4/9) inside such that

y = (-4/9)x2 + (16/9)x - (16/9) + 7.............Then (-16/9) + 7 = (-16/9) + (63/9) = 47/9

so, y = (-4/9)x2 + (16/9)x + (47/9)

3 0

3 years ago