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3 years ago

What are the solutions of the equation x^4+ 95x^2-500=0? Use factoring to solve

Mathematics

2 answers:

Westkost [7]3 years ago

7 0

Answer:

x^4+100x^2-5x^2-500=0

x^2(x^2+100)-5(x^2+100)=0

(x^2+100)(x^2-5)=0

from first expression

x^2+100=0

x^2=-100

x= root under -100

Therefore x=-10

from next expression

x^2-5=0

x^2=5

Or x=2.23

Step-by-step explanation:

levacccp [35]3 years ago

3 0

Answer:

x = ± sqrt(5)

x = ±10i

Step-by-step explanation:

x^4+ 95x^2-500=0

What two numbers multiply to -500 and add to 95

-5 * 100 = -500

-5 +100 = 95

(x^2 - 5) (x^2 + 100) = 0

Using the zero product property

x^2 -5 =0 x^2 +100 =0

x^2 -5+5 =0 x^2 +100-100 = 0-100

x^2 =5 x^2 = -100

Take the square root of each side

x = ± sqrt(5) x = imaginary numbers

x = ±10i

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alexgriva [62]

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3 years ago

a buret is a tool designed to transfer precise amounts of liquid .A buret initially contains 70.00 millimeters of a solution and

katrin [286]

Let:

Vbu= Volume of the buret

Vbk= Volume of the beaker

A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:

x = Number of drips

a = volume of each drip

$\begin{gathered} Vbu=70-ax \\ Vbk=20+ax \\ \text{where:} \\ a=0.05 \\ Vbu=70-0.05x \\ Vbk=20+0.05x \end{gathered}$

after how many drips will the volume of the solution in the buret and beaker be equal ? Vbu = Vbk:

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1 year ago

The first metacarpal bone is located in the wrist. The scatterplot below shows the relationship between the length of the first

gulaghasi [49]

The question is incomplete so I am writing the complete question below and attaching the scatter plot as well.

The first metacarpal bone is located in the wrist. The scatterplot below shows the relationship between the length of the first metacarpal bone and height for 9 people. The line of best fit is also shown

How many of the nine people have an actual height that differs by more than 3 centimeters from the height predicted by the line of best fit?

Answer:

4 people have an actual height that differs by more than 3 cm from the height predicted by the line of best fit.

Step-by-step explanation:

The question is asking us to identify which people have a height that is more than 3 cm greater or more than 3 cm less then the height predicted by the line of best fit. Hence, we need to look at the outliers of the line if best fit i.e. the points which do not lie on the line. We need to select the points that differ by 3 or more cm.

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The second outlier at 4.3 has an actual height of 175 cm but the line of best fit shows a height of 167 cm. There is a difference of 8 cm hence this person also has an actual height which differs by more than 3 cm from the line of best fit.

At 4.8 cm metacarpal bone height, the person's actual height is 172 cm but the graph shows a height of 176 cm hence this person also has an actual height which differs by more than 3 cm from the line of best fit.

At 4.9 cm on the x-axis, the person has an actual height of 183 cm but the line of best fit shows 178 cm so this person also has an actual height which differs by more than 3 cm from the line of best fit.

So, in total there are 4 people out of 9 whose heights differ by more than 3 cm from the line of best fit.

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3 years ago

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Molodets [167]

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Step-by-step explanation:

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