What are the solutions of the equation x^4+ 95x^2-500=0? Use factoring to solve
2 answers:
Answer:
x^4+100x^2-5x^2-500=0
x^2(x^2+100)-5(x^2+100)=0
(x^2+100)(x^2-5)=0
from first expression
x^2+100=0
x^2=-100
x= root under -100
Therefore x=-10
from next expression
x^2-5=0
x^2=5
Or x=2.23
Step-by-step explanation:
Answer:
x = ± sqrt(5)
x = ±10i
Step-by-step explanation:
x^4+ 95x^2-500=0
What two numbers multiply to -500 and add to 95
-5 * 100 = -500
-5 +100 = 95
(x^2 - 5) (x^2 + 100) = 0
Using the zero product property
x^2 -5 =0 x^2 +100 =0
x^2 -5+5 =0 x^2 +100-100 = 0-100
x^2 =5 x^2 = -100
Take the square root of each side
x = ± sqrt(5) x = imaginary numbers
x = ±10i
You might be interested in
Answer:
1:2
Step-by-step explanation:
4:8 chances that you will spin a 5 or more.
8:16 chances that you will spin it two times in a row.
If he cut the loaf into equal pieces, then told you 1/3 was left you could check the even multiples of three. Such as six. So he could have 2 pieces left of his loaf if he cut them into six pieces because 1/3 = 2/6
Answer:
41.8 years
Step-by-step explanation:
From
A= 39000
r = 10.5%
P = $ 485
n=12
t = the unknown
t= [ ln(A) - ln(P) ] / n[ln(1 + r/n)]
t= ln 39000 - ln 485/ 12[ln(1+0.105/12)]
t= 10.57 - 6.18/0.105
t= 41.8 years
Answer: 13 times
Step-by-step explanation:
78 / 6 = 13 times
<span>5(2x - 7)
