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3 years ago

Suppose you subtract –7 from the quotient of –16 and –4. What is the answer

Mathematics

2 answers:

Lelechka [254]3 years ago

3 0

Answer: 11

Step-by-step explanation: -16 / -4 = 4

4 - (-7) = 11

ozzi3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

19 1/2 is 3/4 of what number?

steposvetlana [31]

Answer:

19.5 = 0.75x

x = 26

I hope this finds you well and have a great day.

7 0

3 years ago

Given the second order homogeneous constant coefficient equation y′′−4y′−12y=0 1) the characteristic polynomial ar2+br+c is r^2-

Vitek1552 [10]

Answer:

The initial value problem $y(x) = 4 e^{-2x} -3 e^{6 x}$

Step-by-step explanation:

Step1:-

a) Given second order homogenous constant co-efficient equation

$y^{ll} - 4y^{l}-12y=0$

Given equation in the operator form is $(D^{2} -4D-12)y=0$

Step 2:-

b) Let f(D) = $(D^{2} -4D-12)y$

Then the auxiliary equation is $(m^{2} -4m-12)=0$

Find the factors of the auxiliary equation is

$m^{2} -6m+2m-12=0$

m(m-6) + 2(m-6) =0

m+2 =0 and m-6=0

m=-2 and m=6

The roots are real and different

The general solution $y = c_{1} e^{-m_{1} x} + c_{2} e^{m_{2} x}$

the roots are $m_{1} = -2 and m_{2} = 6$

The general solution of given differential equation is

$y = c_{1} e^{-2x} + c_{2} e^{6 x}$

Step 3:-

C) Given initial conditions are y(0) =1 and y1 (0) =-26

The general solution of given differential equation is

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$ .....(1)

substitute x =0 and y(0) =1

$y(0) = c_{1} e^{0} + c_{2} e^{0}$

$1 = c_{1} + c_{2}$ .........(2)

Differentiating equation (1) with respective to 'x'

$y^l(x) = -2c_{1} e^{-2x} + 6c_{2} e^{6 x}$

substitute x= o and y1 (0) =-26

$-26 = -2c_{1} e^{0} + 6c_{2} e^{0}$

$-2c_{1} + 6c_{2} = -26$ .............(3)

solving (2) and (3) by using substitution method

$substitute c_{2} =1- c_{1}$ in equation (3)

$-2c_{1} + 6(1-c_{1}) = -26$

on simplification , we get

$-2c_{1} + 6(1)-6c_{1}) = -26$

$-8c_{1} = -32$

dividing by'8' we get $c_{1} =4$

substitute $c_{1} =4$ in equation $1 = c_{1} + c_{2}$

so $c_{2} = 1-4 = -3$

now substitute $c_{1} =4 and c_{2} =-3$ in general solution

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$

$y(x) = 4 e^{-2x} -3 e^{6 x}$

now the initial value problem

$y(x) = 4 e^{-2x} -3 e^{6 x}$

7 0

4 years ago

Plot a point on the coordinate plane to represent each of the ratio values in the table. Time (h) Distance (km) able displaying

Effectus [21]

Answer:

Refer the attached graph.

Step-by-step explanation:

Given : Time (h) Distance (km) able displaying Time in hours in one column and Distance in kilometers in the other. The time column contains 1, 3, 6, and 9. The distance column contains 2, 6, 12, and 18.

To plot : The points on the coordinate plane.

Solution :

Time is independent variable so it is taken on x-axis.

Distance is taken on y-axis.

x y

1 2

3 6

6 12

9 18

When we plot these points in the coordinate plane, we get a linear equation.

The linear equation form is $y=2x$

Refer the attached graph.

4 0

3 years ago

PLEASE ANSWER ASAP WORTH 45+ POINTS. FIRST TO ANSWER GETS BRAINLIEST

Arlecino [84]

Answer:

325.28

Step-by-step explanation:

Cross Multlipy

6 0

3 years ago

3x + 3 − x + (−7) > 6 what is x

WARRIOR [948]

3x+3-x+(-7)>6

combine like terms on left side

2x-4>6

add 4 to both sides 2x>10

x=10/2 = 5

x>5

6 0

3 years ago