All categories

3 years ago

SOLVE FOR X!! (will mark brainliest)

Mathematics

2 answers:

nordsb [41]3 years ago

5 0

Answer:

Step-by-step explanation:

Since it is a 90° angle we can say that 3x-15+2x+10 = 90.

3x-15+2x+10 = 90

5x-5=90

5x=95

x=19

By solving this we find that x is equal to 19.

34kurt3 years ago

3 0

Answer:

Step-by-step explanation:

3*19 = 57

57 - 15 = 42

2*19 = 38

38 + 10 = 48

48 + 42 = 90

(As this is a 90 degree angle)

You might be interested in

What is 7 4/5 + 8 8/9

Paladinen [302]

7 4/5 = 7 36/45
8 8/9 = 8 40/45
+----------
15 75/45
15 75/45 = 16 30/45

7 0

3 years ago

Question 6 of 10<br><br> f(x) = 5x + 1) – 3<br> g(x) = 4<br> Find (f - g)(x).

alexdok [17]

Answer:

Answer:

5x + 6

Step-by-step explanation:

(f-g)(x) is nothing but f(x) - g(x)

f(x) is |5x + 1| - 3 and g(x) is 4 so the equation is [|5x+1| - 3] - [4]

Once this is solved, the answer is 5x - 6. Since there's absolute value, remove the negative and change it to a positive to get the answer 5x + 6.

4 0

2 years ago

What adds to be 10 and multiplies to be 24

svet-max [94.6K]

Let x and y be the 2 numbers

x + y = 10
x*y = 24
------------

4 and 6

6 0

4 years ago

Please help c: 10 points

finlep [7]

Area of trapezoid = 1/2 (sum of parallel sides) × (perpendicular distance between them)

DС = 2 + 12 + 2 = 16 in

Area = 1/2 (16 + 12) × 9 = 14 × 9 = 126 in²

8 0

3 years ago

Problem 5. Buses arrive at 116th and Broadway at the times of a Poisson arrival process with intensity λ arrivals per hour. Thes

Shtirlitz [24]

Answer:

Step-by-step explanation:

The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.

If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ

Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be

μ = 0.4λ / 3

The expected number of hours for the event "THIRD M6 arrives", let's say X is

E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ

= 7.5 / λ

The variance of event X is =

$Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}$

6 0

3 years ago