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3 years ago

What is the slope of a line that is parallel to y=3/4x+2

1 answer:

4 0

A line that is parallel to another has exactly the same slope as the other.

so a parallel line to that line above, will have the same slope hmmm what is the slope of <span>y=3/4x+2 anyway?

well, notice, since it's already in slope-intercept form </span> $\bf y=\stackrel{slope}{\cfrac{3}{4}}x~~\stackrel{y-intercept}{+2}$

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Marizza181 [45]

Answer:

18 pots.

Step-by-step explanation:

10/2 to get one of the longs. 5(2) to get the other one. 10.

8/4 to get one of the wides. 2(2) to get the other one. 4.

There are 4 corners so there are 4 extra pots. 4.

Add the numbers: 4+4+10. 18

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2 years ago

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2 years ago

A store is selling lemons at 2 for $3. Each lemon yields 2 tablespoons of lemon juice. How much will it cost to buy enough lemon

igor_vitrenko [27]

Answer:

It will cost $6 to buy enough lemons.

Step-by-step explanation:

Consider the provided information.

To make a 9-inch lemon pie requiring 1/2 cup of lemon juice.

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7 0

3 years ago

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Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

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2 years ago

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