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3 years ago

13

What is the slope of a line that is parallel to y=3/4x+2

1 answer:

k0ka [10]3 years ago

4 0

A line that is parallel to another has exactly the same slope as the other.

so a parallel line to that line above, will have the same slope hmmm what is the slope of <span>y=3/4x+2 anyway?

well, notice, since it's already in slope-intercept form </span> $\bf y=\stackrel{slope}{\cfrac{3}{4}}x~~\stackrel{y-intercept}{+2}$

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A grocery store so the six pack of bottled water for $3.79 a 12 pack for $6.89 which package cost The least per bottle explain y

il63 [147K]

Easiest way to find out the answer to this is to find out the price of every water bottle. To do that you have to divide the whole value by the amount of water bottles. (3.79/6 & 6.89/12) The first one should equal something around .63 each and the second should be around .57. Technically the second pack is cheaper than the other by around .6 cents.

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3 years ago

giving brainlest if explained and showed work please help! i just need it explained so i can understand it!

lawyer [7]

Answer:

2 tablespoons

Step-by-step explanation: he divided the 6 by two to get three so I divided the 4 by two to get 2

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3 years ago

Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

<u>So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.</u>

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3 years ago

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Anastasy [175]

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