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3 years ago

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For a movie stunt, an empty truck with a mass of 2000 kg goes 10 m/s and runs into a stopped car of mass 1000 kg. The truck then

keeps moving and pushes the car along with it.
If there are no other forces acting on this system, which best describes the results of the collision?

The collision is perfectly elastic.
Kinetic energy stays the same.
The momentum after the collision is greater than the momentum before the collision.
The speed of the combined vehicles is less than the initial speed of the truck.

1 answer:

gizmo_the_mogwai [7]3 years ago

7 0

Answer:

D. The speed of the combined vehicles is less than the initial speed of the truck.

Explanation:

Ik this is late

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At a separation distance of 0.500-m, two like-charged balloons experience a repulsive force of 0.320 N. If the distance is is de

soldi70 [24.7K]

Answer:

2.9 N

Explanation:

When the separation distance, r, is 0.5 m, the electrostatic force is 0.32 N. Electrostatic force is given as:

F = (k * q1 * q2) / r²

Where F = force acting on the balloons

k = Coulombs constant

Therefore:

0.32 = (k * q1 * q2) / 0.5²

=> k * q1 * q2 = 0.32 * 0.5² ------------(1)

When the distance is decreased by 3, that is r = r/3 = 0.5/3

F = (k * q1 * q2) / (0.5/3)² ------------(2)

Putting (1) into (2):

=> F = (0.32 * 0.5²) / (0.5/3)²

F = (0.32 * 0.5² * 3²) / 0.5²

F = 2.9 N

Therefore, the force would be 2.9 N

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3 years ago

How do u calculate momentum

Helga [31]

Answer:

Explanation:

To calculate the momentum of a moving object multiply the mass of the object times its velocity. The symbol for momentum is a small p. So, the momentum of the object is calculated to be 8.0 kg-m/s. Note the unit for momentum.

5 0

4 years ago

Two cyclists, who weigh the same and have identical bicycles, ride up the same mountain, both starting at the same time. Joe rid

RSB [31]

Answer:

Option-A

Explanation:

In the given question, two cyclists of equal weight are riding the same mountain with cycles of the same weight but Joe reaches the top before Bob.

This scenario can be explained in terms of power and if we ignore the force of wind resistance and friction. Power refers to the work done per unit time, therefore, P= W/t. Since Joe rides up straight earlier than Bob shows that Joe has exerted more power than Bob that is the amount of work done by the Joe is greater than Bob.

Thus, Option-A is the correct answer.

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4 years ago

Three ideal polarizing filters are stacked, with the polarizing axis of the second and third filters at 21 degrees and 61 degree

kvv77 [185]

Answer:

1

When second polarizer is removed the intensity after it passes through the stack is

$I_f_3 = 27.57 W/cm^2$

2 When third polarizer is removed the intensity after it passes through the stack is

$I_f_2 = 102.24 W/cm^2$

Explanation:

From the question we are told that

The angle of the second polarizing to the first is $\theta_2 = 21^o$

The angle of the third polarizing to the first is $\theta_3 = 61^o$

The unpolarized light after it pass through the polarizing stack $I_u = 60 W/cm^2$

Let the initial intensity of the beam of light before polarization be $I_p$

Generally when the unpolarized light passes through the first polarizing filter the intensity of light that emerges is mathematically evaluated as

$I_1 = \frac{I_p}{2}$

Now according to Malus’ law the intensity of light that would emerge from the second polarizing filter is mathematically represented as

$I_2 = I_1 cos^2 \theta_1$

$= \frac{I_p}{2} cos ^2 \theta_1$

The intensity of light that will emerge from the third filter is mathematically represented as

$I_3 = I_2 cos^2(\theta_2 - \theta_1 )$

$I_3= \frac{I_p}{2}(cos^2 \theta_1)[cos^2(\theta_2 - \theta_1)]$

making $I_p$ the subject of the formula

$I_p = \frac{2L_3}{(cos^2 \theta [cos^2 (\theta_2 - \theta_1)])}$

Note that $I_u = I_3$ as $I_3$ is the last emerging intensity of light after it has pass through the polarizing stack

Substituting values

$I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (61-21)])}$

$I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (40)])}$

$=234.622W/cm^2$

When the second is removed the third polarizer becomes the second and final polarizer so the intensity of light would be mathematically evaluated as

$I_f_3 = \frac{I_p}{2} cos ^2 \theta_2$

$I_f_3$ is the intensity of the light emerging from the stack

substituting values

$I_f_3 = \frac{234.622}{2} * cos^2(61)$

$I_f_3 = 27.57 W/cm^2$

When the third polarizer is removed the second polarizer becomes the

the final polarizer and the intensity of light emerging from the stack would be

$I_f_2 = \frac{I_p}{2} cos ^2 \theta_1$

$I_f_2$ is the intensity of the light emerging from the stack

Substituting values

$I_f_2 = \frac{234.622}{2} cos^2 (21)$

$I_f_2 = 102.24 W/cm^2$

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3 years ago

Formulas in the solutions.

Nutka1998 [239]

Answer:

1) The Newton's law the Hulk is most closely demonstrating is <em>the Third Law of motion</em>

Newton's third law of motion states that action and reaction are equal and opposite.

2) The reason why the Newton's Law the Hulk is most closely demonstrating is the Newton's Third Law of Motion is that according to Newton's Third Law of motion, forces exist in pairs, the action of the Hulk when he leaps upward by pushing against the the Earth (which can be assumed stationary in relation to the Hulk), is equal to the reaction of the Earth, which moves down slightly, away from its initial position.

However, due to the large mass of the Earth, compared to the mass of the Hulk, the downward motion of the Earth due to the reaction force (equal to the force with which the Hulk leaps) is negligibly small, such that the Earth can absorb the Hulk's leap force by reacting mainly locally, at the leap point by forming a crater, while the Earth in general, remains in the same place

Explanation:

6 0

3 years ago