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alexira [117]
3 years ago
9

The area of a rectangle is 72 cm2. State the dimensions of the rectangle with the least perimeter. Calculate the perimeter.

Mathematics
1 answer:
Nitella [24]3 years ago
5 0
We know that
<span>Of all the rectangles having same area, square has the least perimeter
</span>
area of square=x²
where
x is the length side of the square
A=72 cm²
72=x²
x=√72-----> x=6√2 cm

Perimeter of square=4*x------> 4*(6√2)-----> P=24√2 cm
P=33.94 cm

the answer is
the perimeter is equal to 24√2 cm or 33.94 cm

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What is the volume of a regular pyramid having a base area of 24 in.² and a height of 6 inches?
Assoli18 [71]

Answer:

48 in³

Step-by-step explanation:

The volume (V) of a pyramid is calculated as

V = \frac{1}{3} × area of base × height

here area of base = 24 and height = 6, so

V = \frac{1}{3} × 24 × 6 = 8 × 6 = 48 in³

3 0
3 years ago
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3 years ago
I really need help with this my deadline is very soon​
Harman [31]

Answer:

(3)\ y = -x

(5)\ y = -3x -2

Step-by-step explanation:

Required

The equation in slope intercept form

Solving (3):

m = -1

(x_1,y_1) =(4,-4)

The equation in slope intercept form is:

y = m(x - x_1) + y_1

This gives:

y = -1(x - 4) -4

Expand

y = -x + 4 -4

y = -x

Solving (5):

m = -3

(x_1,y_1) = (1,-5)

The equation in slope intercept form is:

y = m(x - x_1) + y_1

This gives:

y = -3(x - 1) - 5

Expand

y = -3x + 3 - 5

y = -3x -2

8 0
3 years ago
Can someone please help me
salantis [7]

Using Pythagorean theorem

\\ \sf\longmapsto P^2=H^2-B^2

\\ \sf\longmapsto P^2=6^2-5^2

\\ \sf\longmapsto P^2=36-25

\\ \sf\longmapsto P^2=11

\\ \sf\longmapsto P=3.2

4 0
2 years ago
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A sample of an unknown liquid has a volume of 12.0 mL and a mass of 6 g. What is its density?
NemiM [27]
Density = Mass/Volume
Density = 6/12 = 0.5 g/mL or 0.5 kg/L

6 0
3 years ago
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