The modulus of complex number can be computed with this equation:
|z|=sqrt(Re(z)^2+Im(z)^2)
z = -2-6i
Re(z)=-2, so Re(z)^2=4
Im(z)=-6, so Im(z)^2=36
|z|=sqrt(36+4)=sqrt(40)=6.3
<span>By similarity of triangles we have the following relationship:</span>
<span> (x) / (6) = (18) / (9)</span>
<span> Simplifying we have:</span>
<span> (x) / (6) = 2</span>
<span> Clearing the value of x we have:</span>
<span><span> x = 6 * 2</span></span>
<span><span> X = 12</span></span>
<span><span> Answer:</span></span>
<span><span> The value of x for this case is equal to:</span></span>
<span><span> <span>X = 12</span></span>
</span>
T is more than -4. Remember that -4 is not included.
Answer:
Area = 74.1 square units
Step-by-step explanation:
Area of the composite figure = Area of the rectangle + Area of the semicircle
Area o the rectangle = Length × Width
= 10 × 6
= 60 square units
Area of the semicircle = ![\frac{1}{2}\pi r^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r%5E%7B2%7D)
Here, r = radius of the semicircle
For the semicircle with radius =
= 3 units
Area = ![\frac{1}{2}\pi (3)^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cpi%20%283%29%5E%7B2%7D)
= 4.5π
= 14.14 units²
Total area of the composite figure = 60 + 14.14
= 74.14 square units ≈ 74.1 square units