What is the 1st quartile in the data set 65 90 100 72 88 55 73

Mrs. Potts can make 5 dozen ravioli in 1 hour. Write and solve a direct variation equation to find many she can make in 2 1/2 ho

erica [24]

A direct variation generally has the equation Y=KX
Because Mrs. Potts makes 5 dozen ravioli in 1 hour, this will be the K value.
(5 dozen/1 hr)
To figure out how many she can make in 2 1/2 hrs. You use 5 dozen/1 hr as the K value and multiply that by 2 1/2 hrs (the X value).
The hrs will cancel out and you will be left with the number of ravioli made in 2 1/2 hrs.

5 0

3 years ago

20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

ANSWER:

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

SOLUTION:

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago

Mine A is 225 feet underground and Mine B has an elevation of -223 feet. Which mine is further underground

LUCKY_DIMON [66]

Answer: Mine A

Step-by-step explanation: Mine A is further underground because elevation means height and when it’s shows a number that is negative that means underground. 225 is greater than 223. So Mine A is further underground.

3 0

3 years ago

Read 2 more answers

Please help me! [One Step Inequalities]

WITCHER [35]

n - 8 < -8

< is similar to = in this case

n < -8 + 8
n < 3

The answer would be bubble #3.

7 0

2 years ago

Which choice shows the students listed in order from who has the least amount of money to who has the greatest amount of money

exis [7]

Step-by-step explanation:

Should be Emily, Morgan, Kali, Rosa

6 0

3 years ago