Write an expression (4x-2)*6(2x+7) in the standard form of a quadratic expression, ax^2+bx+c. What are the values of the coeffic
ients of each term and the constant term?
2 answers:
Answer:
see explanation
Step-by-step explanation:
given (4x - 2) × 6(2x + 7), then
= 6(4x - 2)(2x + 7) ← expand factors using FOIL
= 6(8x² + 28x - 4x - 14)
= 6(8x² + 24x - 14) ← distribute
= 48x² + 144x - 84 ← in standard form
with a = 48, b= - 144, c = - 84
Answer:
a=48
b=-192
c=84
Step-by-step explanation:
figure it out yourself :3 jk Idrk
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