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Digiron [165]
3 years ago
12

This composite shape is a rectangle with a semicircle attached on one end. The diameter of the semicircle is 6 feet.

Mathematics
2 answers:
Ugo [173]3 years ago
3 0

As we can see on the picture we have a rectangle and half of circle.

The areas for half circle and rectangle are:

A_{rectangle}=a\cdot b \\A_{halfcircle}=\frac{A_{circle}}{2}=\frac{\pi r^2}{2}

The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.

Now we calculate the areas.

A_{rectangle}=10\cdot 6=\underline{60} \\A_{halfcircle}=\frac{3.14\cdot3^2}{2}=\underline{14.13} \\A_{total}=A_{rectangle}+A_{halfcircle} =60+14.13=\boxed{74.13\approx74}

The area of the figure is approximately 74ft squared.

Hope this helps.

r3t40

RUDIKE [14]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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The total amount, a, in dollars, that Mitra earns is a = 14.6h, where h is the number of hours that she works. What is the const
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Answer:

\begin{gathered} sin(\theta)=\frac{-\sqrt{7}}{4} \\ cos(\theta)=-\frac{3}{4} \\ tan(\theta)=\frac{\sqrt{7}}{3} \\ csc(\theta)=-\frac{4}{\sqrt{7}} \\ sec(\theta)=-\frac{4}{3} \\ cot(\theta)=\frac{3}{\sqrt{7}} \end{gathered}

Step-by-step explanation:

If theta is in the third quadrant, draw the diagram to easily identify the other trigonometric relations:

Solve for the missing leg of the triangle, using the Pythagorean theorem:

\begin{gathered} \text{ adjacent}^2+\text{ opposite}^2=\text{ hypotenuse}^2 \\ -3^2+\text{ opposite}^2=4^2 \\ \text{ opposite=}\sqrt{16-9} \\ \text{ opposite=}\sqrt{7} \end{gathered}

Therefore, for the trigonometric relationships:

\begin{gathered} \text{ sin\lparen}\theta)=\frac{opposite}{hypotenuse} \\ \text{ cos\lparen}\theta)=\frac{adjacent}{hypotenuse} \\ tan(\theta)=\frac{opposite}{adjacent} \\ csc(\theta)=\frac{hypotenuse}{opposite} \\ sec(\theta)=\frac{hypotenuse}{adjacent} \\ cot(\theta)=\frac{adjacent}{opposite} \end{gathered}

Now, substitute and solve for the relations:

\begin{gathered} sin(\theta)=\frac{-\sqrt{7}}{4} \\ cos(\theta)=-\frac{3}{4} \\ tan(\theta)=\frac{\sqrt{7}}{3} \\ csc(\theta)=-\frac{4}{\sqrt{7}} \\ sec(\theta)=-\frac{4}{3} \\ cot(\theta)=\frac{3}{\sqrt{7}} \end{gathered}

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