Question

H e l p m e

Answer 1

Answer Step-by-step explanation:

$\huge\boxed{A)-1}$

$The~average~rate~of~change~of~the~given~quadratic~function~on~the$ $interval~0$ ≤ x ≤$4$ $is~the~slope~of~the~secant~line~connecting~the~points~(0,f(0))~and~(4,f(4)).$

$The~average~rate~of~change~is:$

$=\frac{f(4)-f(0)}{4-0}$

$Now,from~the~graph,f(0)~is~0~and~f(4)~is~-4.$

$We~plug~in~these~values~to~obtain;$

$=\frac{-4-0}{4-0}$

$And~then,this~simplifies~to:$

$=\frac{-4}{4}$

$which~is~obviously:$

$=-1$

$Thus,~the~average~rate~of~change~for~the~given~quadratic~function$ $whose~graph~is~shown~on~0$ ≤ x ≤ $4~is~=-1.$