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3 years ago

Please help. What is the answer!?

Mathematics

1 answer:

sdas [7]3 years ago

6 0

Answer:

4/19

Step-by-step explanation:

because, in the sequence they are subtracting 3 in each one it goes so, first it was 16-3= 13, 13-3= 10, and so on. Hope I helped :3

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A sample of bacteria is growing at an hourly rate of 14% according to the continuous exponential growth function. The sample beg

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Answer:

125.0272

Step-by-step explanation:

7 (1.14)^22

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3 years ago

What does each angle term mean? OAT ITT EAT SATT ?

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3 years ago

HELPP ME PLZZZ THIS IS MY LAST QUESTION

cestrela7 [59]

Answer:

a. y = 3x - 11

b. y = -1/3 x - 1

Step-by-step explanation:

The line on the graph increases by 3 every time it moves over 1. This means that the slope of the given line is 3.

a. When 2 equations are parallel, their slopes are the same, so the slope of this equation will be 3. To find the y-intercept, plug in the values of the slope and the given point (3, -2) into the equation y = mx + b:

-2 = 3(3) + b

-2 = 9 + b

-11 = b

The y-intercept is -11. Now we can write our equation:

y = 3x - 11

b. When 2 lines are perpendicular, their slopes are negative reciprocals. The negative reciprocal of 3 is -1/3. We can use the slope and the given point (3, -2) to find the y-intercept:

-2 = -1/3(3) + b

-2 = -1 + b

-1 = b

The y-intercept is -1. Now we can write our equation:

y = -1/3x - 1

Hope this helps :)

8 0

3 years ago

Read 2 more answers

Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15. An equation of the li

pochemuha

Answer:

$\displaystyle y = \frac{3}{5}\, x + (-2)$ .

Step-by-step explanation:

The slope of a line in a plane would be $m$ if the equation of that line could be written in the slope-intercept form $y = m\, x + b$ for some constant $b$ .

Find the slope of the given line by rearranging its equation into the slope-intercept form.

$3\, y = (-5)\, x + 15$ .

$\displaystyle y = \frac{(-5)}{3} \, x + 5$ .

Thus, the slope of the given line would be $(-5) / 3$ .

Two lines in a plane are perpendicular to one another if and only if the product of their slopes is $(-1)$ .

Let $m_{1}$ and $m_{2}$ denote the slope of the given line and the slope of the line in question, respectively.

Since the two lines are perpendicular to each other, $m_{1}\, m_{2} = (-1)$ . Apply the fact that the slope of the given line is $m_{1} = (-5) / 3$ and solve for $m_{2}$ , the slope of the line in question.

$\begin{aligned}m_{2} &= \frac{(-1)}{m_{1}} \\ &= \frac{(-1)}{(-5) / 3} = \frac{3}{5}\end{aligned}$ .

In other words, the slope of the line perpendicular to $5\, x + 3\, y = 15$ would be $(3 / 5)$ .

If the slope of a line in a plane is $m$ , and that line goes through the point $(x_{0},\, y_{0})$ , the equation of that line in point-slope form would be:

$(y - y_{0}) = m\, (x - x_{0})$ .

Since the slope of the line in question is $(3 / 5)$ and that line goes through the point $(5,\, 1)$ , the equation of that line in point-slope form would be: