Question

2. A solid is in the form of a right circular cylinder with a hemisphere at one end and a cone at the other end the radius of the common base 8cm and the heights of the cylindrical and conical portions are 10cm and 6cm respectively find the total surface area of the solid [π=3.14]
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Answer 1

Answer:

Total Surface Area of Solid = C.s.a of hemisphere+C.s.a of cone+C.s.a of Cylinder

slant height of cone=√h²+r²

=√6²+8²

=√100

=10cm

height of cone = 10 cm

radius of hemisphere =radius of cone=radius of cylinder=8cm

T.S.A of solid=2πrh+2πr²+πrl

=πr[2h+2r+l]

=3.14*8[2*10+2*8+10]

=25.12[36+10]

=25.12*46

=1155.52 cm²

Explanation:

hope this helps

Answer 2

Answer:

Height of the cylindrical part and cone are 10cm and 6cmrespectively

Radius of cone , cylinder and hemi sphere=3.5cm

r=3.5cm for both Cylinder and cone

The area of canvas required=Surface area of hemishphere,cylinder and cone parts of tent

A=2πr

2

+2πrh+πr(

h

2

+r

2

)

A=2π×3.5×3.5+2π×3.5×10+π×3.5(

3.5

2

+6

2

)

A=373.3cm

2