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almond37 [142]
3 years ago
14

I ish confuzzled plz help

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

If your looking for the slope-intercept from of each one then its:

1) \frac{4}{3} + 0 or \frac{4}{3}

2) 0x + 5

3) \frac{3}{2}x - 3

4) \frac{1}{5} x + 0 or \frac{1}{5} x

5) x + 5 or 1x + 5

Hope this helped!

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peyton learned that the brown bear at a local zoo weigh 1,578 pounds. about how much more does the brown bear weigh than the pol
Alexxx [7]
Since there is no number for the number of pounds for the polar bear, you would use p to represent polar bears. The expression would be: 1578 - p. Good luck
5 0
3 years ago
The base of a triangle is 44. If the area is 242 square feet, then what is the height of the triangle in feet?
stich3 [128]

Hello!

\large\boxed{ 11 ft}

Recall that the area of a triangle is:

A = 1/2(bh) where:

b = base of the triangle

h = height of the triangle

Plug in the given values:

242 = 1/2(44h)

Simplify:

242 = 22h

Divide both sides by 22:

242/22 = 22h/22

h = 11 feet.

4 0
3 years ago
Read 2 more answers
Together, Bob and Tom take 2 hours to get the yard work done. If Bob works alone, it takes him 6 hours. How long would it take T
gladu [14]
<span>It would take him three hours</span>
3 0
3 years ago
Which of the points A(−6, 2), B(0, 0), C(4, −2), D(−12, 6), E(−10, 10) belong to the graph of direct variation y=− 1 2 x?
vovangra [49]

ANSWER

B(0, 0),

EXPLANATION

The given points are A(−6, 2), B(0, 0), C(4, −2), D(−12, 6), E(−10, 10).

The equation of the direction variation is

y =  - 12x

The point that belongs the graph of the direct variation must satisfy the variation equation.

Note that the graph of direct variation equation passes through the origin therefore the point (0,0) satisfies it.

0=-12(0)

0=0

This is true

The other points do not satisfy this variation equation, hence they do not lie on its graph

5 0
4 years ago
Find the area and perimeter of this shape please. show work needed
ra1l [238]

Answer: A=448+196pi, P=60+14pi

Step-by-step explanation:

I'm assuming that the figures which appear to be semicircles are semicircles and that the quadrilateral is a rectangle.

The perimeter is 16 + 16 + 28 + (28/2)(pi)= 60+14pi

area is area of rectangle + area of semicircle

= (16)(28)+(pi)(14)(14)=448+196pi

7 0
2 years ago
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