Answer:
<h3>m∠1 = 41°</h3><h3>m∠2 = 41°</h3>
Step-by-step explanation:
<h3>m∠1 = m∠2</h3>
x = 5°,
m∠1 = (6x + 11)°
Step-by-step explanation:
Adding 10 to both sides of the original equation gets us q = 6(r + 1) + 10. Since q is equal to h(r), we get h(r) = 6(r + 1) + 10 = 6r + 16.
<h3><u>Answer</u> :</h3>
![\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}](https://tex.z-dn.net/?f=%5Cbigstar%5C%3A%5Cboxed%7B%5Cbf%7B%5Cpurple%7Bx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%7D%3D%5Corange%7B%28%5Csqrt%5Bn%5D%7Bx%7D%29%5Em%7D%7D%7D)
Let's solve !
![:\implies\sf\:(\sqrt[2]{25})^3](https://tex.z-dn.net/?f=%3A%5Cimplies%5Csf%5C%3A%28%5Csqrt%5B2%5D%7B25%7D%29%5E3)
<u>Hence, Oprion-D is correct</u> !
Answer:
cot theta = -√3
Step-by-step explanation:
we are given that cos theta = - √3/2 within the range 180° < theta < 270° and
since cos theta = adj/hyp
adj = - √3
hyp = 2
Get the opposite using the pythagoras theorem
hyp^2 = opp^2 + adj^2
2² = opp² + (-√3)²
4 = opp² + 3
opp² = 4-3
opp² = 1
opp = 1
tan theta = opp/adj
tan theta = - 1/√3
Recall that cot theta = 1/tan theta
cot theta = 1/(-1/√3)
cot theta = -√3
We will calculate this by using ratios and because these two triangles are similar, which is very important.
Explanation:
We see that the FG = 9 corresponds to the VU = 21. Therefore, FH = 18 corresponds to the UW = x.
9 : 21 = 18 : x
x = (21*18)/9
x = 378/9
x = 42.
The correct answer is B. 42.
