Distance from P to the x-axis = 2x distance from P to the yz-plane
<span>Distance to the x-axis of a point P=(x,y,z) is (y^2+z^2)^1/2 </span>
<span>Distance to the yz-plane of a point P=(x,y,z) is x </span>
<span>So your equation is: </span>
<span>(y^2+z^2)^1/2 = 2x </span>
<span>=> y^2 + z^2 = 4x^2 </span>
<span>=> y^2 + z^2 - 4x^2 = 0
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B= Exactly one solution
-6y+9y= 3y
3y+13=8y-3
3y=8y-16
-5y=-16
Answer:
ghgyeryeughheyyrgjehrgb ehgryeurghekdrdrg dhgidrg
36-40= -4
36 subtracted by 40 equals negative 4
-4
