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3 years ago

Which statements are true given the histogram? Check all that apply.

Mathematics

2 answers:

vova2212 [387]3 years ago

8 0

Answer:

(a)The histogram is symmetrical. FALSE

(b) The histogram is evenly distributed. FALSE

(d) More texts were sent from 6 p.m.-8 p.m. than from 8 p.m.-10 p.m. FALSE.

(e)The peak from 4 p.m.-6 p.m. means that the highest number of texts was sent during this interval. TRUE

Step-by-step explanation:

(a)The histogram is symmetrical.

FALSE, as the histogram has no line of symmetry.

(b) The histogram is evenly distributed.

FALSE, the histogram is not evenly distributed as there is no data in the

10: AM to 3:00 PM slot.

TRUE, the data shows that the most texts were sent in afternoon and evening as it has the highest peaks in the given slot.

(d) More texts were sent from 6 p.m.-8 p.m. than from 8 p.m.-10 p.m.

The number of texts sent from 6 p.m.-8 p.m = 19

The number of texts sent from 8 p.m.-10 p.m = 29

But, 19 < 29

Hence, the given statement is FALSE.

(e)The peak from 4 p.m.-6 p.m. means that the highest number of texts was sent during this interval. TRUE, the highest peak indicates the highest number of texts sent in the given interval.

Margarita [4]3 years ago

5 0

Answer:

3,5

Step-by-step explanation:edg 2021

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On a trip, Duke encounters some road construction that slows him down. While he is able to go 60 mph on the highway and 40 mph t

natulia [17]

Answer:

Time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

Step-by-step explanation:

Speed by which Duke travels a distance on highway $d_1$ = 60 mph

Let the time taken to travel on highway = $t_1$ hours

Distance traveled = $60t_1$ miles

Speed in the city = 40 mph

Let the time taken = $t_2$ hours

Distance traveled in the city = $40t_2$ miles

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Let the time spend on the construction = $t_3$ hours

Distance traveled on the construction = $20t_3$ miles

Since, total distance covered = 380 miles

$d_1+d_2+d_3=60t_1+40t_2+20t_3$

He spends one half the time on the highway as he does on the construction,

$t_3=2t_1$

Total time spent in the trip = 11 hours

Therefore, $t_1+t_2+t_3=11$

$t_1+t_2+2t_1=11$

$t_2=11-3t_1$

From equation (1),

$60t_1+40(11-3t_1)+20(2t_1)=380$

$60t_1-120t_1+40t_1+440=380$

$440-20t_1=380$

$20t_1=440-380$

$t_1=\frac{60}{20}$

$t_1=3$ hours

$t_2=11-3t_1=2$ hours

$t_3=2t_1=6$ hours

Therefore, time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

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3 years ago

What is 6f-23=[-5] plz help

xz_007 [3.2K]

Add 23 from both sides
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6(3)-23
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