Which Two triangles are similar to A ADB

Which is a step in the process of calculating successive discounts of 8% and 10% on a $50 item

Paraphin [41]

Answer:

The process of calculating successive discounts of 8% and 10% on a $50 item is take 10% of $46.

Step-by-step explanation:

As given

successive discounts of 8% and 10% on a $50 item .

First find out for 8 % discount

8% is written in the decimal form

= 0.08

8 % of $50 item = 0.08 × 50

= $ 4

Price of item after 8% discount = 50 - 4

= $46

First find out for 10 % discount

10% is written in the decimal form

= 0.1

8 % of $48 item = 0.1× 46

= $4.6

Price of item after 8% discount = 46 - 4.6

= $41.4

Therefore in the successive discounts of 8% and 10% on a $50 item is $41.4 .

5 0

2 years ago

What is the number of possible outcomes if three quarters are tossed and the total numbers of heads and tails are counted? A) 2

Gre4nikov [31]

Answer:

D). 8.

Step-by-step explanation:

Each quarter will come up heads or tails - that is 2 possibilities.

So for 3 tosses the number of outcomes is 2*2*2 = 8.

3 0

2 years ago

Read 2 more answers

1 point CA If a rectangular prism has the width of 5. t What would the scale factor be? Round to Type your answer... 3 4 4 1 Giv

Sunny_sXe [5.5K]

We know that the original width was 5, and that after the enlargement the width is 45. To calculate the scale factor we divide the final width between the original one, then:

$\frac{45}{5}=9$

Therefore the scale factor is 9.

7 0

3 months ago

Fill in the blank (correctly). 20 points each.

lyudmila [28]

Distributing same key numbers

7 0

2 years ago

The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

5 0

2 years ago