Answer:
![0.46=\frac{23}{50}](https://tex.z-dn.net/?f=0.46%3D%5Cfrac%7B23%7D%7B50%7D)
Step-by-step explanation:
To write any decimal as a fraction you divide by 1 and multiply by a number (ranging from 10, 100, 1000 etc.) that will make 0.46 a whole number, this will explain:
Let x = ![\frac{0.46}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B0.46%7D%7B1%7D)
10x = ![10*\frac{0.46}{1} =\frac{4.6}{10}](https://tex.z-dn.net/?f=10%2A%5Cfrac%7B0.46%7D%7B1%7D%20%3D%5Cfrac%7B4.6%7D%7B10%7D)
100x =
this is our perfect fraction, now we simplify later
100x - 10x = ![\frac{46}{100} -\frac{4.6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B46%7D%7B100%7D%20-%5Cfrac%7B4.6%7D%7B10%7D)
90x =
this is to confirm both fractions are equal
x is the same as
as
as
but here x =
because a fraction has to have no decimals.
So 0.46 is equal any of these values, as a fraction, on the other hand, it's improperly equal to
here I divided by 2 to bring down the proper fraction. (fraction at its simplest form)
Answer:
Step-by-step explanation:
Assuming the number of tickets sales from Mondays is normally distributed. the formula for normal distribution would be applied. It is expressed as
z = (x - u)/s
Where
x = ticket sales from monday
u = mean amount of ticket
s = standard deviation
From the information given,
u = 500 tickets
s = 50 tickets
We want to find the probability that the mean will be greater than 510. It is expressed as
P(x greater than 510) = 1 - P(x lesser than or equal to 510)
For x = 510
z = (510 - 500)/50 = 0.2
Looking at the normal distribution table, the probability corresponding to the z score is 0.9773
P(x greater than 510) = 1 - 0.9773 = 0.0227
1, 5, 4, 2, 3 in that order