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3 years ago

8

Why is there no tutor

2 answers:

kupik [55]3 years ago

7 0

I am not sure why there isn’t any tutors

pickupchik [31]3 years ago

4 0

I think you have to follow someone and ask them to be your tutor.

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Decimal greater than 1 write the word form and expanded form for each 3.4

True [87]

3.4, 3 + 0.4, three point four
5.8, 5 + 0.8, five point eight
6.2, 6 + 0.2, six point two

5 0

3 years ago

Find the slope of the line that passes through \left(10,8\right)(10,8) and \left(1,9\right)(1,9).

sdas [7]

Answer:

m = -1/9

Step-by-step explanation:

7 0

2 years ago

there are 3 liters of apple juice at a school party. 10 students want to drink all the apple juice, Andi all want to get exactly

pochemuha

Answer:

0.3 L

Step-by-step explanation:

3 L / 10 students = 3/10 = 0.3 Liters per student

4 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

. In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one stu

Sergeeva-Olga [200]

Answer: B. $H_0:p_1=p_2$

$H_a:p_1>p_2$

Step-by-step explanation:

Let $p_1$ be the proportion of all U.S. adults that smoked in 1995. Let $p_2$ denote the proportion of all U.S. adults that smoked in 2000.

Objective for the study : Whether the proportion of U.S. adults that smoke declined during the 5-year period between the samples.

i.e. $p_1>p_2$

Alternative hypothesis $(H_a)$ is the statement containing population parameter that shows there is significant difference between the groups being tested.

⇒ $H_a:p_1>p_2$

Null hypothesis $(H_0)$ is the statement containing population parameter that shows there is no significant difference between the groups being tested.

⇒ $H_0:p_1=p_2$

Hence, The hypotheses to test in this problem are

$H_0:p_1=p_2$

$H_a:p_1>p_2$

Hence, the correct answer is B. $H_0:p_1=p_2$

$H_a:p_1>p_2$

8 0

3 years ago