Answer:
The expression of this question can be given as:
Expression:
*ip + 1
Explanation:
In this question, it is given that ip variable has been declared and initialized and the ip variable is in the first half of the array. It finds the expression whose value is after the element of the array that ip points. So the expression to this question is *ip + 1. Where * is used to define ip variable as a pointer and its value is increased by 1 that is given in the question.
Simple and easy user interface design can help the users understand what they can do on the website, without confusion when they are loading on the website.
Best practice on the users experiences can help the users to visit the website easily and get what they want as fast as possible. It is the way to improve a website understandability.
Answer:
Following are the code to this question:
list_val = input()#defining a integer variable for input value
test_grades = list(map(int, list_val.split()))#defining test_grades as a list
sum_extra = -999 #defining sum_extra that holds negative integer value
sum_extra = 0#defining sum_extra that holds value
for y in range(len(test_grades)):#defining a for loop to check range of list
if(test_grades[y] > 100):# defining if block that check list value is greater then 100
sum_extra = sum_extra + (test_grades[y] - 100)#use sum_extra variable to hold extra value and add this value
print('Sum extra:', sum_extra)#print value
Output:
101 83 107 90
Sum extra: 8
Explanation:
In the above code a, "list_val" variable is declared, that uses an input method to input the values and declared a "test_grades" variable that uses a list method to add all values in the list.
In the next step, the "sum_extra" variable is declared, which holds some values and defines a for loop to check the range of the "test_grades", and define a if block, that checks list value is greater than 100. If the condition is true, it will remove the extra value, and add it into the sum_extera variable and add its value, and at the last use, print variable to print its value.
Here you go. I added a constructor and a toString overload to make the object creation and printing as easy as possible.
public class student {
private String _id;
private String _name;
private String _address;
public student(String id, String name, String address) {
_id = id;
_name = name;
_address = address;
}
public String toString() {
return "Id: " + _id + "\nName: " + _name + "\nAddress: "+ _address;
}
public static void main(String[] args) {
student s1 = new student("S12345", "John Doe", "Some street");
System.out.println(s1);
}
}
Answer: Identifying sequences
Explanation:
Since the user wants to know if there are any particular activities that the customers engage in, or the types of purchases made in the month before or after purchasing select items from your store, therefore, the data mining software can be used in identifying sequences.
In this case, the data mining software can't be used in classifying data whether into structured or unstructured data. Furthermore, the identification of clusters and associations aren't the correct answers.
Therefore, the best option is B.
