I programmed in batch before so I know a lot of things!
You can ping a website to test your latency.
ping google.com
I have a ton of tricks in cmd (Command Prompt). Message me if you want.
I'd suggest he uses
LOOKUP Function.
You can use the LOOKUP function when you need to look in a
single column or row and find a value from the same position in a corresponding
column or row. We have a much improved VLOOKUP that can also be used to search
one row or column or multiple rows and columns.
The option that can be used to identify and analyze which characteristic of OSPF signifies this is known to be Low overhead, fast convergence.
<h3>What is OSPF about?</h3>
The OSPF is known to be called an open Shortest Path First protocol.
It belongs to the family of IP Routing protocols as it serves as Interior Gateway Protocol (IGP) used mainly for the Internet, and the option that can be used to identify and analyze which characteristic of OSPF signifies this is known to be Low overhead, fast convergence.
See full question below
A network administrator has asked Robin, a network engineer, to use OSPF (Open Shortest Path First) along with RIP (Routing Information Protocol) on an edge router in a network so that it demands more memory and CPU power for calculations but keeps network bandwidth to a minimum with a very fast convergence time. Identify and analyze which characteristic of OSPF signifies this.
Shared data
Low overhead, fast convergence
Stability
Multi-vendor routers
Learn more about OSPF from
brainly.com/question/14604232
#SPJ1
Answer:
/*
Find Largest and Smallest Number in an Array Example
This Java Example shows how to find largest and smallest number in an
array.
*/
public class FindLargestSmallestNumber {
public static void main(String[] args) {
//array of 10 numbers
int numbers[] = new int[]{32,43,53,54,32,65,63,98,43,23};
//assign first element of an array to largest and smallest
int smallest = numbers[0];
int largetst = numbers[0];
for(int i=1; i< numbers.length; i++)
{
if(numbers[i] > largetst)
largetst = numbers[i];
else if (numbers[i] < smallest)
smallest = numbers[i];
}
System.out.println("Largest Number is : " + largetst);
System.out.println("Smallest Number is : " + smallest);
}
}
/*
Output of this program would be
Largest Number is : 98
Smallest Number is : 23
*/
Explanation: