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Mice21 [21]
3 years ago
11

What is the length of the hypotenuse of the triangle when x=7?

Mathematics
1 answer:
Anika [276]3 years ago
7 0

Answer:

c=57.8

Step-by-step explanation:

6*7+4=46

5*7=35

c= 46^2+35^2=57.80138

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9x-5y=29 find the value of y when x equals 1
svp [43]
9x - 5y = 29....when x = 1
9(1) - 5y = 29
9 - 5y = 29
-5y = 29 - 9
-5y = 20
y = 20/-5
y = -4 <==
7 0
4 years ago
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How do u do this? PLz show work!!!!
marissa [1.9K]
N:7=x remainder 2
⇒ n= 7*x +2
 
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⇒ the remainder is 1
4 0
3 years ago
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I need help with this one , please .  (13)^2(13)^-4(13)^5 = 13^_____    to what power ?    Can you explain please
Galina-37 [17]
13^2*13^{-4}*13^5= 13^7*13^{-4}\to\boxed{13^3}

When you have exercices like this tipe you write the base and add the exponents.the exponents are: 2; -4  and 5 so you put them in a sum:

2+ (-4) + 5=

=2 -4+5=

=7 -4=

=3
6 0
3 years ago
Please help need answer fast‼️
Bess [88]

Answer:

The second one is D.

Step-by-step explanation:

7 0
3 years ago
A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place
Alborosie

Answer:

23 years

Step-by-step explanation:

Step 1: Calculate the rate constant (k) for the radioactive decay

A radioactive substance with initial concentration [A]₀ decays to 97% of its initial amount, that is, [A] = 0.97 [A]₀, after t = 1 year. Considering first-order kinetics, we can calculate the rate constant using the following expression.

ln [A]/[A]₀  = - k.t

k = ln [A]/[A]₀ / -t

k = ln 0.97 [A]₀/[A]₀ / -1 year

k = 0.03 year⁻¹

Step 2: Calculate the half-life of the substance

We will use the following expression.

t_{1/2} = ln2/ k = ln 2 / 0.03 year⁻¹ = 23 years

4 0
3 years ago
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