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3 years ago

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Which statements about the local maximums and

1 answer:

8_murik_8 [283]3 years ago

8 0

In terms of communication, information is expressed either as the content of a message or through direct or indirect observation. That which is perceived can be construed as a message in its own right, and in that sense, information is always conveyed as the content of a message.

Information can be encoded into various forms for transmission and interpretation (for example, information may be encoded into a sequence of signs, or transmitted via a signal). It can also be encrypted for safe storage and communication.

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Check all that apply

kogti [31]

Answer:

A & C

Step-by-step explanation:

The equation for a circle is (x – h)^2 + (y – k)^2 = r^2, with the center being at (h,k). On the x-axis would mean the x coordinate would equal 0, therefore A and C are your answers.

Hope I helped! :)

7 0

3 years ago

Read 2 more answers

14. The least common multiple of 2, 5, 6, and 9 is

CaHeK987 [17]

Answer:

A

Step-by-step explanation:

8 0

3 years ago

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Which expression is equivalent to - 1 2/5 + 2 1/3

Ulleksa [173]

Answer:

C. 2 1/3 - 1 2/5

Step-by-step explanation:

Let a = - 1 2/5 and b = 2 1/3

<u>We have a + b, lets compare with the options:</u>

A) a + (- b) = a - b, no
B) a - b, no
C) b + a = a + b, yes
D) b - a, no

6 0

2 years ago

A commuter must pass through 5 traffic lights on her way to work and will have to stop at each one that is red. She estimates th

sergij07 [2.7K]

Answer:

(a) The mean or expected value of <em>X </em>is 2.2.

(b) The standard deviation of <em>X</em> is 1.3.

Step-by-step explanation:

Let <em>X</em> = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of <em>X</em> id provided.

The formula to compute the mean or expected value of <em>X </em>is:

$\mu=E(X)=\sum x.P(X=x)$

The formula to compute the standard deviation of <em>X </em>is:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}$

The formula of E (X²) is:

$E(X^{2})=\sum x^{2}.P(X=x)$

(a)

Compute the expected value of <em>X</em> as follows:

$E(X)=\sum x.P(X=x)\\=(0\times0.06)+(1\times0.25)+(2\times0.35)+(3\times0.15)+(4\times0.13)+(5\times0.06)\\=2.22\\\approx2.2$

Thus, the mean or expected value of <em>X </em>is 2.2.

(b)

Compute the value of E (X²) as follows:

$E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58$

Compute the standard deviation of <em>X</em> as follows:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3$

Thus, the standard deviation of <em>X</em> is 1.3.

4 0

3 years ago

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Which equation is represented by the graph below?

Westkost [7]

I would say y = ln x + 4
you can use a graphing calculator

7 0

3 years ago

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