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2 years ago

If Logx (1 / 8) = - 3 / 2, then x is equal to

Mathematics

1 answer:

snow_tiger [21]2 years ago

8 0

Answer:

Let's solve!

Step-by-step explanation:

$logx^{\frac{1}{8} } = -\frac{3}{2}$

$then$

$10^{-\frac{3}{2}} = x^{\frac{1}{8} }$

$(10^{-\frac{3}{2} })^{8} = (x^{\frac{1}{8} })^{8}$

$x = 10^{3*4} = 10^{-12}$

$x= 10^{-12}$

If the equation looks like this, then it has the solution

$x= 10^{-12}$

Another answer is

√x = 2 or x = 4

I hope this helps!

For more help:

<u>brainly.com/question/9719370</u>

<u>brainly.com/question/7126917</u>

<u>brainly.com/question/3505855</u>

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Josh and Anthony have a lemonade stand. They charge $1 for 2 cups of lemonade. They sell 14 cups each afternoon. Is it reasonabl

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No, because 14 cups of lemonade divided by 2 is 7, or, $7. $7 multiplied by 3 ( 3 afternoons) is 21, or, $21.

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Step-by-step explanation:

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2 years ago

Which expression demonstrates the use of the commutative property of addition in the first step of simplifying the expression (–

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The expression (21 + 5i) + (-1 + i) demonstrates the commutative property of addition for (-1 + i) + (21 + 5i)

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An equation is an expression that shows the relationship between two or more number and variables.

Given the expression:

(-1 + i) + (21 + 5i)

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1 year ago

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Answer:

1353.13

Step-by-step explanation:

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2 years ago

(12x + y + z = 26

mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

$\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}26\\17\\23\end{array}\right]$ .

Step 3:

The linear system B is represented as

$\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}23\\17\\26\end{array}\right]$ .

Step 4:

The linear system C is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}4\\11\\12\end{array}\right]$ .

Step 5:

The linear system D is represented as

$\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\z\end{array}\right]$ $= \left[\begin{array}{ccc}12\\11\\4\end{array}\right]$ .

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

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2 years ago