Answer:
5 weeks
Step-by-step explanation:
Let's find how much money she saves a week by multiplying the decimal form of 60% and $70.
To get the decimal form of a percent you have to move the decimal to the left twice, like this: 60 ---> .60
Now that we have the decimal form of the percent we can multiply it by the 70 to find how much she saves a week:
(70)(.6) = 42
Therefore, Kendra saves $42 each week.
To find how many weeks it will take Kendra to buy the game system you divide $210 by the $42. Like this:
(210)/(42) = 5
All in all, it will take Kendra 5 weeks to save enough money to buy a game system that costs $210.
<em>I hope this helps!!</em>
<em>- Kay :)</em>
<em />
Answer:
15 units
Step-by-step explanation:
K(8, 6) and J(-4, -3)
Distance between 2 points

Thus using the formula above,
distance between points J and K
![= \sqrt{ {[8- (-4)]}^{2} + {[6- (-3)]}^{2} } \\ = \sqrt{ {12}^{2} + {9}^{2} } \\ = \sqrt{225} \\ = 15 \: units](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%5B8-%20%28-4%29%5D%7D%5E%7B2%7D%20%20%2B%20%20%7B%5B6-%20%28-3%29%5D%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%20%7B12%7D%5E%7B2%7D%20%20%2B%20%20%7B9%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B225%7D%20%20%5C%5C%20%20%3D%2015%20%5C%3A%20units)
14. B (4, -2)
15. I am not exactly sure about this one but I would say either A or B.
Differnce of 2 pefect squares
a^2-b^2=(a-b)(a+b)
(p^2)^2-9^2=(p^2-9)(p^2+9)
p^2-9=(p-3)(p+3)
factored is
(p-3)(p+3)(p^2+9)
Answer: At $21.85, the supply will equal to demand.
Step-by-step explanation:
Since we have given that
Demand function is given by

Supply function is given by

According to question, we need to find the price for which the supply equals the demand, i.e. Equilibrium price and quantity.

So, at $21.85, the supply will equal to demand.