Answer:
k
Step-by-step explanation:
Answer: y = |x+4|
Explanation:
Imagine that the graph of y = |x| is carved in stone so it cannot move. What we can move though is the xy axis. If we move the xy axis 4 units to the right, then this gives the illusion the V shaped curve is moving 4 units to the left. It goes opposite whatever movement you do to the xy axis.
If we replaced x with x+4, then this moves the xy axis 4 units to the right.
Therefore, going from y = |x| to y = |x+4| will have the V shaped curve moving 4 units to the left.
No not at all because 1 and 3 are prime numbers and they are not integers
The minimum is the vertex
y=a(x-h)^2+k
(h,k) is vertex
given
(4,-8)
y=a(x-4)^2-8
find a
given
(2,0) and (6,0)
find a
0=a(2-4)^2-8
0=a(2)^2-8
0=4a-8
8=4a
divide 4
2=a
other one
0=a(6-4)^2-8
0=a(2)^2-8
0=4a-8
8=4a
divide 4
2=a
the function is
y=2(x-4)²-8 or expanded
y=2x^2-16x+24
Answer:
1. X > 8
2. a. X < 5
Step-by-step explanation:
1. 3x - 8 > 16
+8. +8
3x > 24
divide both sides by 3
x >8
2. 2x - 1 < 9
+1. +1
2x < 10
divide both sides by 2
x < 5