2x-10+4x-18=4x
6x-28=4x
2x=28
x=14 is the solution
6x-28=4x is equivalent
Hope this helped!
As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1
As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.
Given, a△b=a^2-b/b-a^2
now 4△3 = (4^2-3) / (3-4^2)
4△3 = (16-3) / (3-16)
4△3 = 13 / -13
4△3 = -1
Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.
- Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.
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x=0
because you must
determine the undefined range
write all numerators above the common denomonator
multiply the parenthesis
collect the alike terms
remove parenthesis
eliminate the opposites collect the like terms
set the numerator equal to 0
divide both sides by 6
check if thesolution is the defined range
if so then you would find your answer X=0
Answer:
648
Step-by-step explanation:
(25 - 9 + 2)^2 / 3x6
= 108 x 6
= 608
follow BODMAS and you'll get it
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