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Troyanec [42]
3 years ago
10

What is the sum of the geometric sequence -4,24,-144...if there are 8 term? A.-959,781 B. 29,637 C. 26,661 D. 959,780 PLEASE HEL

P
Mathematics
2 answers:
Serggg [28]3 years ago
7 0
It is d because I know it guys trust me it is easy.

iogann1982 [59]3 years ago
6 0

Answer:

The sum of 8 terms of series is 959,780

D is correct

Step-by-step explanation:

Given: -4, 24, -144, ......

There are 8 terms.

We need to find the sum of 8 terms.

First term, a=-4

Common ratio, r=-6

a_n=-4\cdot(-6)^{n-1}

Sum of 8 term

Sum=a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8

Sum=\sum_{n=1}^{8}a_n

Sum=-4+24-144+864-5184+31104-186624+1119744

Sum=959,780

Hence, The sum of 8 terms of series is 959,780

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Margaret [11]

If two triangles are similar, then their side lengths are proportional.

RS / JK = RT / JL

5 / x = 4 / 7

4x = 35

x = 35/4 = 8.75

RT / JL = TS / LK

4 / 7 = 6 / (y + 2)

42 = 4(y + 2)

42 = 4y + 4

4y = 38

y = 38/4 = 9.5

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8 0
2 years ago
What is the sum of all values of m that satisfy 2m (squared) -16m+8=0?
vodomira [7]
<h2>Steps:</h2>

So for this, we will be completing the square to solve for m. Firstly, subtract 8 on both sides:

2m^2-16m=-8

Next, divide both sides by 2:

m^2-8m=-4

Next, we want to make the left side of the equation a perfect square. To find the constant of this perfect square, divide the m coefficient by 2, then square the quotient. In this case:

-8 ÷ 2 = -4, (-4)² = 16

Add 16 to both sides of the equation:

m^2-8m+16=12

Next, factor the left side:

(m-4)^2=12

Next, square root both sides of the equation:

m-4=\pm \sqrt{12}

Next, add 4 to both sides of the equation:

m=4\pm \sqrt{12}

Now, while this is your answer, you can further simplify the radical using the product rule of radicals:

  • Product rule of radicals: √ab = √a × √b

√12 = √4 × √3 = 2√3.

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<h2>Answer:</h2>

In exact form, your answer is m=4\pm \sqrt{12}\ \textsf{OR}\ m=4\pm 2\sqrt{3}

In approximate form, your answers are (rounded to the hundreths) m=7.46, 0.54

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