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Troyanec [42]
3 years ago
10

What is the sum of the geometric sequence -4,24,-144...if there are 8 term? A.-959,781 B. 29,637 C. 26,661 D. 959,780 PLEASE HEL

P
Mathematics
2 answers:
Serggg [28]3 years ago
7 0
It is d because I know it guys trust me it is easy.

iogann1982 [59]3 years ago
6 0

Answer:

The sum of 8 terms of series is 959,780

D is correct

Step-by-step explanation:

Given: -4, 24, -144, ......

There are 8 terms.

We need to find the sum of 8 terms.

First term, a=-4

Common ratio, r=-6

a_n=-4\cdot(-6)^{n-1}

Sum of 8 term

Sum=a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8

Sum=\sum_{n=1}^{8}a_n

Sum=-4+24-144+864-5184+31104-186624+1119744

Sum=959,780

Hence, The sum of 8 terms of series is 959,780

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If a = -35, b = 10 cm and c = -5, verify that:
Murljashka [212]

Step-by-step explanation:

(i). a+(b+c) = (a+b)+c

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7 0
2 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

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2 years ago
The inverse of this equation
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Answer:

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