Hello! I believe she would have 58,000 at the end of her fourth year. Hope this helps. :)
The answer is 500 seconds it’s 5.33 minutes.
Answer:
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
5)
Adj = 14
Hyp = 26
∠X
so use
CAH
Cos(X) = 14/26
X = arcCos(14/26)
X = 57.421°
X = 57.4 ° ( rounded to nearest 10th )
6)
∠X
Hyp = 46
Opp = 12
use SOH
Sin(x) = 12/46
X = arcSin(12/46)
X = 15.121°
X = 15.1 ° ( rounded to nearest 10th )
7)
∠X
Adj = 29
Opp = 24
use TOA
Tan(x) = 29 / 24
X = arcTan( 29 /24)
X = 50.389
X = 50.4 ° ( rounded to nearest 10th )
8)
∠X
Adj = 22
Opp = 6
use TOA agian
Tan(x) = 6 / 22
X = arcTan(6/22)
X = 5.194
X = 5.2 ° ( rounded to the nearest 10th )
:)
Answer: The slope is: "3" ; which does not appear among the answer choices given.
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The slope, "m" is calculated as follows:
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Given two coordinates on a line;
m = (y₂ − y₁) / (x₂ − x₁) ;
__________________________________________
We are given the following 2 (TWO) coordinates:
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1) (5,2) ; which is: (x₁ ,y₁) ; so x₁ = 5 ; y₁ = 2 ; AND:
2) (7,8); which is: (x₂ ,y₂) ; so x₂ = 7; y₂ = 8 ;
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So; m = (y₂ − y₁) / (x₂ − x₁) = (8−2) /.(7−5) = 6/2 = 3 .
m = 3. The slope is: 3 ; which does not appear among the answer choices given.
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Alternately,
______________________________________________
We are given the following 2 (TWO) coordinates:
__________________________________________
1) (7,8) ; which is: (x₁ ,y₁) ; so x₁ = 7 ; y₁ = 8 ; AND:
2) (5,2); which is: (x₂ ,y₂) ; so x₂ = 5; y₂ = 2 ;
______________________________________________
So; m = (y₂ − y₁) / (x₂ − x₁) = (2−8) / (5−7) = -6/-2 = 3 .
m = 3. The slope is 3 ; which does not appear among the answer choices given.
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When the squared terms are of different signs, the equation generally describes a hyperbola. This one has its vertices at x=±30, so the parameters of interest are
domain: (-∞, -30] ∪ [30, ∞)
range: (-∞, ∞)
