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saveliy_v [14]
3 years ago
11

Find the geometric mean between 8 and 18. Write answer as a simplified radical. No Decimals!!!!

Mathematics
1 answer:
Crank3 years ago
4 0

Answer: Therefore, the geometric mean of 8 and 18 is 12. Therefore, the geometric mean of 8 and 18 is 12.

Step-by-step explanation:

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PLS HELP ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Ivan

Answer:

Option C. bar graph is the answer.

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3 years ago
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A new car is purchased for $17,000 and over time its value depreciates by one half every 3 years. What is the value of the car 1
Jet001 [13]

Answer:

The answer is "$238".

Step-by-step explanation:

Current worth= \$ 17,000

depreciates by \frac{1}{2} in 3 years.

time=  19 years

depreciates rate=?

Using formula:

\to \text{Worth=  Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}

\to A_t=A_0(1-\frac{r}{100})^t

calculates depreciate value in 3 year = \frac{1}{2} \times 17,000

                                                              = 8,500

so,

A_t=8,500\\\\A_0=17,000\\\\t=3\ years

\to A_t=A_0(1-\frac{r}{100})^t\\\\\to 8,500= 17,000(1-\frac{r}{100})^3\\\\\to \frac{8,500}{17,000}= (1-\frac{r}{100})^3\\\\\to \frac{1}{2}= (1-\frac{r}{100})^3\\\\\to (\frac{1}{2})^{\frac{1}{3}}= (1-\frac{r}{100})\\\\\to 0.793700526 = (1-\frac{r}{100})\\\\\to \frac{r}{100} = (1-0.793700526)\\\\\to \frac{r}{100} = (1-0.8)\\\\\to r= 0.2 \times 100 \\\\\to r= 20 \%

depreciates rate= 20%

\to \text{Worth=  Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}

= \$ 17,000 (1- \frac{20}{100})^{19}\\\\= \$ 17,000 (1-0.2)^{19}\\\\= \$ 17,000 (0.8)^{19}\\\\= \$ 17,000 \times 0.014\\\\= \$ 238

4 0
3 years ago
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Evaluate the expression 6/5x when x=20
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Answer:

24

Step-by-step explanation:

6 divided by 5 times 20 =24

6/5*20= 24

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2 years ago
Ill give brainliest please help :(
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Answer:

okay so god,dog,now,won,noon,doom,mood,not,ton,pool

Step-by-step explanation:

7 0
3 years ago
The authors of a paper presented a correlation analysis to investigate the relationship between maximal lactate level x and musc
ArbitrLikvidat [17]

Answer:

a) Sample correlation coefficient, r = 0.7411

bi) test statistic, t = 4.102

bii) P-value = 0.000736

Step-by-step explanation:

a) The formula for the sample correlation coefficient is given by the formula:

r = \frac{S_{xy} }{\sqrt{S_{xx} S_{yy} }} }

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r = \frac{7408.225}{\sqrt{2648130.357*36.7376} }

r = 0.7511

b)

i) formula for the test statistic is given by the formula:

t = \frac{r\sqrt{n-1} }{\sqrt{1 - r^{2} } }

sample size, n = 4

t = \frac{0.7511\sqrt{14-1} }{\sqrt{1 - 0.7511^{2} } }

t = 4.102

ii) Degree of freedom, df = n -2

df = 14 -2

df = 12

The P-value is calculate from the degree of freedom and the test statistic using excel

P-value =(=TDIST(t,df,tail))

P-value = (=TDIST(4.1,12,1)

P-value = 0.000736

4 0
3 years ago
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