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Masja [62]
2 years ago
14

257 whole number,integer number, or rational number

Mathematics
2 answers:
aliya0001 [1]2 years ago
8 0
257 is a whole number, interger, and a rational number.
oksano4ka [1.4K]2 years ago
5 0
257 counts as all of them 
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Serggg [28]
For the function w,w(9)

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(-1,2) and (3,4) what's the midpoint ? Show work please.
babymother [125]
The midpoint formula is:
( \frac{x1 + x2}{2} ,  \frac{y1+y2}{2} )
Insert your coordinates.
(\frac{-1+3}{2},  \frac{2+4}{2}) =  (\frac{2}{2},  \frac{6}{2} )
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(1,3)
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3 years ago
Solve the following equation.<br> x^2 + 6x − 40 = 0
jonny [76]

Answer:

x = 4 and -10

Step-by-step explanation:

Given the equation

x²+6x-40= 0

The common factors to use for the factorisation are +10 and -4

x²+(10x-4x)-40=0

(x²+10x)-(4x-40) = 0

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(x-4)(x+10) = 0

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8 0
3 years ago
From a barrel of colored marbles you randomly select 7 blue, 5 yellow, 8 red, 4 green, and 6 purple marbles. Find the experiment
kozerog [31]
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4 0
3 years ago
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I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

=(2x^2+2x-3)+(-x+3)

Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

4 0
3 years ago
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