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mr Goodwill [35]
3 years ago
9

3. Solve for the side length of BA and AC. * (image attached)

Mathematics
2 answers:
horrorfan [7]3 years ago
6 0
Ba = 8,ac = 16 is the correct one
aliya0001 [1]3 years ago
3 0

Answer:

D. BA = 8, AC = 8√3

Step-by-step explanation:

First, because this is a right triangle, refer to the trigonometric ratios:

tangent = opposite side/adjacent side

sine = opposite side/hypotenuse

cosine = adjacent side/hypotenuse

BA is the opposite side to the angle measure given, ∠C—which is 30°—and we have the measure of BC. BC is the hypotenuse, as it is across from the right angle of the right triangle. So we can use sine:

sine = opposite side/hypotenuse

sin(30) = BA/16

sin(30) / 1 = BA / 16

Cross multiply:

BA = sin(30) (16)

BA = 8

AC is the adjacent side to the angle measure given, ∠C—which is 30°—and we have the measure of BC. BC is the hypotenuse, as it is across from the right angle of the right triangle. So we can use cosine:

cosine = adjacent side/hypotenuse

cos(30) = AC/16

cos(30) / 1 = AC / 16

Cross multiply:

AC = cos(30) (16)

AC = 8√3

You can check by using the Pythagorean Theorem:

a² + b² = c²

8² + (8√3)² = 16²

64 + 192 = 256

256 = 256

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Step-by-step explanation:

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given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
ipn [44]

Answer:

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

Step-by-step explanation:

The weekly demand curve of a local wine producer is p= 50-0.1q

p = price

q = quantity

Revenue function R =Price \times Quantity

R=(50-0.1q)q

R=50q-0.1q^2

Cost function: c= 1500+ 10q

Profit function=R(x)-C(x)

Profit function= 50q-0.1q^2-1500-10q

Profit function= 40q-0.1q^2-1500   ----1

We have q = 500 - 10 p using p = 50 − 0.1q

P=-0.1 (500 - 10 p)^2 + 40 (500 - 10 p)- 1500\\P= -10 p^2 + 600 p - 6500

General quadratic equation:ax^2+bx+c=0

On comparing

a = -0.1 , b = 40 , c = -1500

Maximum Profit is at q = \frac{-b}{2a}=\frac{-40}{2(-0.1)}=200

To find price must a bottle of wine be sold to realise maximum profit

p= 50-0.1q

p= 50-0.1(200)=30

Substitute the value of q in profit function(1) get the maximum profit

So, Profit function= 40\left(200\right)-0.1\left(200\right)^{2}-1500=2500

Hence

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

8 0
3 years ago
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