A 3x with an exponet of 3
Whhshsbsbwn Shaka ahahha
Logical answer
:') alright. Break down the composite shape into 2 separate shapes:
The radius of the semi-circle is 14/2=7cm
So the area of the semi-circle is (pi×7^2)/2=77cm^2 to 1 d.p.
The area of the rectangle is 14×20=280cm^2
280+77=357cm^2 is the area of the composite shape
Answer:
![\left(h,\:k\right)=\left(-\frac{3}{2},\:\frac{9}{4}\right),\:p=-\frac{1}{4}](https://tex.z-dn.net/?f=%5Cleft%28h%2C%5C%3Ak%5Cright%29%3D%5Cleft%28-%5Cfrac%7B3%7D%7B2%7D%2C%5C%3A%5Cfrac%7B9%7D%7B4%7D%5Cright%29%2C%5C%3Ap%3D-%5Cfrac%7B1%7D%7B4%7D)
Step-by-step explanation:
![x^2+3x+y=0](https://tex.z-dn.net/?f=x%5E2%2B3x%2By%3D0)
![4\left\bigg(-\frac{1}{4}\right)\left\bigg(y-\frac{9}{4}\right)=\left\bigg(x-\left\bigg(-\frac{3}{2}\right)\right)^2](https://tex.z-dn.net/?f=4%5Cleft%5Cbigg%28-%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5Cleft%5Cbigg%28y-%5Cfrac%7B9%7D%7B4%7D%5Cright%29%3D%5Cleft%5Cbigg%28x-%5Cleft%5Cbigg%28-%5Cfrac%7B3%7D%7B2%7D%5Cright%29%5Cright%29%5E2)
![\bold{\mathrm{Therefore\:parabola\:properties\:are:}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cmathrm%7BTherefore%5C%3Aparabola%5C%3Aproperties%5C%3Aare%3A%7D%7D)
![\left(h,\:k\right)=\left(-\frac{3}{2},\:\frac{9}{4}\right),\:p=-\frac{1}{4}](https://tex.z-dn.net/?f=%5Cleft%28h%2C%5C%3Ak%5Cright%29%3D%5Cleft%28-%5Cfrac%7B3%7D%7B2%7D%2C%5C%3A%5Cfrac%7B9%7D%7B4%7D%5Cright%29%2C%5C%3Ap%3D-%5Cfrac%7B1%7D%7B4%7D)
Answer:
Step-by-step explanation:
![-3x^2-7x-9=F(x)](https://tex.z-dn.net/?f=-3x%5E2-7x-9%3DF%28x%29)
![F(-5)=-75+40-9=-49](https://tex.z-dn.net/?f=F%28-5%29%3D-75%2B40-9%3D-49)
![F(2)=-12-14-9=-35](https://tex.z-dn.net/?f=F%282%29%3D-12-14-9%3D-35)
![f(-5)+f(2)=-49-35=-84](https://tex.z-dn.net/?f=f%28-5%29%2Bf%282%29%3D-49-35%3D-84)