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Ratling [72]
3 years ago
7

Simplify 8x^2-x-12x+2x2​

Mathematics
1 answer:
balu736 [363]3 years ago
3 0

Answer:

Simplify: 8 2 − 1 3 + 2 2

Step-by-step explanation:

Solution: 1 0 2 − 1 3

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Find the equation of the ellipse with the following properties. The ellipse with foci at (0, 6) and (0, -6); y-intercepts (0, 8)
sesenic [268]
Hi, thank you for posting your question here at Brainly.

The general equation of a horizontal ellipse is

(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.

If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,

2b = 16
b = 8
b^2 = 64

The distance between the two foci is 2c. Thus,

2c = 12
c = 6
c^2 = 36

Then, a2 = 64 + 36 = 100. Substituting to the general equation:

x^2/100 + y^2/64 = 1
8 0
3 years ago
Which statement best describes the atoms in a solid​
Ludmilka [50]

Answer:

A solid formed is described when its resistance is tightly secured, and when it refuses to change shapes. It is one of the four fundamental elements. The best answer would be: The atoms are packed together and cannot move around.

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Answer:

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Read 2 more answers
Given the equation y=14x2−5, the minimum is ___ and the range is ___
mel-nik [20]

Answer:

The minimum is -5

The range is y \ge -5

f(14) = 2739

Step-by-step explanation:

Given

y = 14x^2 - 5

Solving (a): The minimum

A quadratic function is represented as:

y = ax^2 + bx + c

If a > 0, then the function has a minimum

By comparison

a = 14 --- the function has a minimum

b = 0

c = -5

To calculate the minimum, we first calculate the following is calculated as:

m = -\frac{b}{2a}

So, we have:

m = -\frac{0}{2*14}

m = 0

So, the minimum is at f(m)

We have: y = 14x^2 - 5

f(0) = 14 *0^2 - 5

f(0) = - 5

Solving (b): The range

In (a), we have:

f(0) = - 5 --- the minimum

This implies that the smallest value of y on the graph is -5.

So, the range is:

r = \{y|y\ge -5\}

Solving (c): f(14)

We have:

y = 14x^2 - 5

So:

f(14) = 14 * 14^2 - 5

f(14) = 2739

4 0
3 years ago
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