Answer:
3.2
Step-by-step explanation:
Check the picture below.
so, let's notice, is really just a 2x20 rectangle with a quarter of a semicircle with a radius of 11.
![\bf \stackrel{\textit{area of a circle}}{A=\pi r^2}~~ \implies A=\pi 11^2\implies A=121\pi \implies \stackrel{\textit{one quarter of that}}{\boxed{A=\cfrac{121\pi }{4}}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\underline{\textit{area of the figure}}}{\stackrel{\textit{rectangle's area}}{(2\cdot 20)}+\stackrel{\textit{circle's quart's area}}{\cfrac{121\pi }{4}}\qquad \approx \qquad 135.03\implies \stackrel{\textit{rounded up}}{135}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20a%20circle%7D%7D%7BA%3D%5Cpi%20r%5E2%7D~~%20%5Cimplies%20A%3D%5Cpi%2011%5E2%5Cimplies%20A%3D121%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bone%20quarter%20of%20that%7D%7D%7B%5Cboxed%7BA%3D%5Ccfrac%7B121%5Cpi%20%7D%7B4%7D%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Cunderline%7B%5Ctextit%7Barea%20of%20the%20figure%7D%7D%7D%7B%5Cstackrel%7B%5Ctextit%7Brectangle%27s%20area%7D%7D%7B%282%5Ccdot%2020%29%7D%2B%5Cstackrel%7B%5Ctextit%7Bcircle%27s%20quart%27s%20area%7D%7D%7B%5Ccfrac%7B121%5Cpi%20%7D%7B4%7D%7D%5Cqquad%20%5Capprox%20%5Cqquad%20135.03%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B135%7D%7D)
Answer: x = 5, y = -1
<u>Step-by-step explanation:</u>
Equation 1: 4x + 2y = 18
Equation 2: 3x - 5y = 20
In order to eliminate one of the variables , find the LCM of either x or y.
<em>I chose to eliminate y.</em> The LCM of 2 & 5 is 10.
Multiply the entire equation so the coefficient of the variable equals the LCM.
Then add the equations and solve for the remaining variable.
5(4x + 2y = 18) --> 20x + 10y = 90
2(3x - 5y = 20) --> <u> 6x - 10y</u> = <u>40 </u>
26x = 130
<u> ÷26 </u> <u>÷26 </u>
x = 5
Next, input x = 5 into either of the equations to solve for y.
Equation 1: 4x + 2y = 18
4(5) + 2y = 18
20 + 2y = 18
<u> -20 </u> <u>-20 </u>
2y = -2
<u> ÷2 </u> <u> ÷2 </u>
y = -1
The answer to the question is B (the second option 4:2)
Answer:
Step-by-step explanation:
line that is parallel to x-axis the slope = 0
an equation is : y= ax+b a = 0
passes through the point (3,5) : y =5 when x = 3 so : b = 5
an equation is : y = 5
