1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ValentinkaMS [17]
4 years ago
10

What is the measure of angle ABC

Mathematics
1 answer:
inysia [295]4 years ago
3 0
1 + 1 = 2 - 1 = 1 hope this helps.

You might be interested in
2n^2 - 20 <br> n= 5 <br> ?????
hjlf
2n^2-20=0
2n^2=20
n^2=20÷2
n^2=10
n=radical 10
5 0
4 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with M = 0.03, \pi = 0.21

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.44\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.44\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.44\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^{2} = (\frac{1.44\sqrt{0.21*0.79}}{0.03})^{2}

n = 382.23

Rounding up

We need a sample size of at least 383.

6 0
3 years ago
Worth lot of points :))))
maxonik [38]

Step-by-step explanation:

slope = (y2 - y1)/(x2 - x1)

-4/3 = (6 - y)/[4-(-2)]

-4/3 = (6-y)/6

(-4/3)×6 = 6-y

-8 = 6-y

y = 6 + 8

= 14

7 0
3 years ago
Read 2 more answers
A runner warmed up for 10 minutes and then takes seven minutes to run each mile. The total time after r miles is 45 minutes how
scoundrel [369]
So our equation to find this can be represented by 7x + 10 = 45.
(x representing miles run)
Just solve for x!

Subtract the 10 from both sides, you've got
 7x = 35
And now to isolate the x, we divide both sides by 7.
Now we're left with just
x = 5!

We can check this by substituting 5 as x in our equation.
7x x 5 + 10 = 45
45 = 45
It's right!

So the runner ran 5 miles total.

Hope this helps!
If I skimmed over this too much, let me know and I'll try to explain the best that I can.
7 0
3 years ago
Simplify <br> 3 2/3 - 2 3/4 =
Rasek [7]

Answer: 11/12

Step-by-step explanation:

1. To solve this problem you can transform the mixed numbers given in the problem to fractions, as you can see below:

3 2/3=(3*3+2)/3=11/3

2 3/4=(4*2+3)/4=11/4

2. Now you must make the substraction of the fraction:

11/3-11/4=11/12

3. Therefore, the answer is 11/12

6 0
4 years ago
Other questions:
  • What are 3 numbers to multiply to equal 750?
    5·1 answer
  • Which of the following shows an inconsistent system of equations?
    10·1 answer
  • A triangle is rotated 180 degrees about the origin. Its image is reflected in the x-axis. The vertices of the final triangle are
    14·1 answer
  • Find the difference. (3 • 1,000) – (2 • 100)
    7·2 answers
  • What is an equivalent expression to 48x - 30?
    7·1 answer
  • Mr. Burr and his daughter live in Corpus Christi, Texas. Mr. Burr’s employer pays 100% of his insurance premium and 50% of the p
    12·1 answer
  • 4 (y - 2) - 3 (y + 2) =
    14·2 answers
  • Andrew needs to call his 8 baseball teammates to make plans for a party at the end of the season if each call takes 5 minutes ho
    10·1 answer
  • What does E stand for?
    15·1 answer
  • Help me please help me
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!