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3 years ago

43x28 what is the whole problem to solve it

Mathematics

2 answers:

Naya [18.7K]3 years ago

6 0

Answer:

1,204

Step-by-step explanation:

43(28) = 1,204

erastovalidia [21]3 years ago

3 0

Answer:

Step-by-step explanation:

43x28=1204

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Solve 50r − 6 = 82r − 70

Basile [38]

Answer:

Step-by-step explanation: 50r - 6= 82r-70

Add 50r to 82r which equals to 132 r

Now add the the 70 to the left side so -6+70 should equal 76.

Now it should look like this 76=132r

To get the value of r you have to divide 76/132 on both sides of the equation and your answer should be 0.57=r

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3 years ago

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What is this number in standard form? plzzzzzzzzz i need this

Nookie1986 [14]

The answer is 82.046

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3 years ago

of the pets in the pet show 5/6 are cats.4/5 of the calico cats what fraction of the pets are calico cats

Bond [772]

The answer is 0.664 because you have to divide 4/5 and 5/6

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3 years ago

What is the rate of return when 25 shares of Stock

7nadin3 [17]

Based on the information given the rate of return is 10.8%.

First step is to find the shares of stock price:

Shares of stock price=25 shares×$30/share

Shares of stock price= $750

Second step is to calculate the total sold price:

Total sold price= $825+$6

Total sold price= $831

Third step is to calculate the Rate of return:

Rate of return=$831-750/$750×100

Rate of return=$81/$750×100

Rate of return=10.8%

Inconclusion the rate of return is 10.8%.

Learn more about rate of return here:brainly.com/question/21691170

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2 years ago

SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as

vovangra [49]

Answer:

a) $P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

$P(Z>1.25)=1-P(Z$

b) $P(400$

$P(-1$

c) $z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(500,100)$

Where $\mu=500$ and $\sigma=100$

We are interested on this probability

$P(X>625)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.25)=1-P(Z$

Part b

We are interested on this probability

$P(400$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(400$

And we can find this probability with this difference:

$P(-1$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1$

Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.8$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

8 0

3 years ago