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2 years ago

43x28 what is the whole problem to solve it

Mathematics

2 answers:

Naya [18.7K]2 years ago

6 0

Answer:

1,204

Step-by-step explanation:

43(28) = 1,204

erastovalidia [21]2 years ago

3 0

Answer:

Step-by-step explanation:

43x28=1204

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Gelneren [198K]

Answer:

the answer is b.11

Step-by-step explanation:

4 0

3 years ago

Using the solubility curve, choose all of the statements that are correct.

irinina [24]

Answer:

See explanation below

Step-by-step explanation:

According to the solubility curve attached, let's analyze each sentence to see which one is correct:

"Solubility of NaCl is least affected by temperature"

True. as you can see in the curve, solubility of NaCl remains almost constant at any value of temperature, so in this case, it does not matter the temperature, the NaCl solubility will be the same.

"completely dissolve 60 g of KBr in 100 g of water at 20 °C"

True. As you can see in the graph, solubility of KBr begins at 60 g, so in 20 °C we have something dissolved there. Actually you have like 70 g dissolved there, so, this is true.

"The solubility of KNO3 is the least affected by changes in temperature"

False. The curve for KNO3 is exponencial, so, changes in temperature do actually affect the solubility.

"100 g of KBr will dissolve completely in 100 g of water at 75 °C"

False. According to the curve, 100 g dissolve when we reach more than 100 °C. At 75 °C only about 85 g of KBr is dissolved.

"if you mix 120 g of NaClO3 in 100 g of water at 10 °C, approximately 30 g will not dissolve"

True. In the graph we can clearly see that at 10 °C only about 90 g is being dissolved so, the rest of the mass is still there as mass.

6 0

2 years ago

Four different lines are drawn on a coordinate plane. The lines all pass through the origin each each line passes through one po

Cloud [144]

Answer:

it's C

Step-by-step explanation:

5 0

3 years ago

in a recent year one United States dollar was equal to about 82 Japanese yen how many Japanese yen are equal to $1,00 $1,000 $10

Yuki888 [10]

In a recent year, one United States dollar was equal to about 82 Japanese. How many Japanese yen are equal $100?$1,000?$10,000
Given is: 

1 USD = 82 Japanese Yen 

Conversion: 

1. 100 USD x 82 JY / 1 USD = 8, 200 Japanese Yen 
2. 1000 USD x 82 JY / 1 USD = 82, 000 Japanese Yen 
3. 10, 000 USD x 82 JY / 1 USD = 820, 000 Japanese Yen

5 0

2 years ago

a teacher and 10 students are to be seated along a bench in the bleachers at a basketball game. In how many ways can this be don

Veronika [31]

Wow !

OK. The line-up on the bench has two "zones" ...

-- One zone, consisting of exactly two people, the teacher and the difficult student.
   Their identities don't change, and their arrangement doesn't change.

-- The other zone, consisting of the other 9 students.
   They can line up in any possible way.

How many ways can you line up 9 students ?

The first one can be any one of 9.   For each of these . . .
The second one can be any one of the remaining 8. For each of these . . .
The third one can be any one of the remaining 7. For each of these . . .
The fourth one can be any one of the remaining 6. For each of these . . .
The fifth one can be any one of the remaining 5. For each of these . . .
The sixth one can be any one of the remaining 4. For each of these . . .
The seventh one can be any one of the remaining 3. For each of these . . .
The eighth one can be either of the remaining 2. For each of these . . .
The ninth one must be the only one remaining student.

   The total number of possible line-ups is

   (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) = 9! = 362,880 .

But wait ! We're not done yet !

For each possible line-up, the teacher and the difficult student can sit

-- On the left end,
-- Between the 1st and 2nd students in the lineup,
-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.

That's 10 different places to put the teacher and the difficult student,
in EACH possible line-up of the other 9 .

So the total total number of ways to do this is

   (362,880) x (10) = 3,628,800 ways.

If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !

4 0

3 years ago