The answer is B. Because there are 8 ribbons in all. 1 ribbon is black. so the equation would be 1/8. Assuming you don't draw the black ribbon on the first try, then you would try again. The second time you draw a ribbon you don't put the ribbon you drew back in. That means there are only 7 ribbons the second time. The 1 black ribbon is still in the bag than the equation would be 1/7. Then you add the two together. So it would be 1/8 + 1/7 = 1/15. Remember to only add the bottom numbers. not the top ones unless they are different colors or objects.
Step-by-step explanation:
RS = 15/ tan57° = 9.7
RT = 15/sin57° = 17.9
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer:
Step-by-step explanation:
<u>We see that:</u>
- y- intercept is b = 0.5, point (0, 0.5)
- Rate of change is m = 1 as each next value of y is greater by 1.
<u>The function is:</u>
Correct choice is A
