Answer:
B. Yes, because it touches the y-axis exactly one time
C. Yes, because each x-value has exactly on corresponding y-value
Answer:
0.5789
Step-by-step explanation:
The successful events would be 34 , 40 41 42 43 44 45 46 47 48 49
The total number of ways 19 when you count from 31 to 49
P(1 four) = 11/19 = 0.5789
Answer
z= 14
Step-by-step explanation:
4( 2z-3) -5(z-6) =3 *20
8z-12-5z+30=60
3z+18=60
3z=60-18
3z=42
z= 14
I think its 210 because there are 7 letters and 3 vowels so the permutation would be 7 P 3.
Well let's see:
The first letter can be any one of 26 .
For each one . . .
The second letter can be any one of the remaining 25.
For each one . . .
The third letter can be any one of the remaining 24.
For each one . . .
The two digits can be any number from 01 to 98 ...
except 11, 22, 33, 44, 55, 66, 77, or 88. (No repetition.)
There are 90 of them.
So the total number of possibilities is (26 · 25 · 24 · 90) .
When I multiply that out, I get 1,404,000 .
I don't know how you got your number, so I can't comment on your
method, but I did find something interesting about your number:
If I assume that you did the three letters the same way I did, then
if I divide your number by (26·25·24), the quotient will show me
how you handled the two digits.
1,263,600 / (26·25·24) = 81 .
That's very intriguing, because it's so close to the 90 sets of digits
that I used. But I don't know what it means, or if it means anything
at all.
