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2 years ago

What is the area of this triangle?

Mathematics

2 answers:

Sindrei [870]2 years ago

5 0

Can you put an image of the triangle???

UNO [17]2 years ago

5 0

Answer:

i see no picture of a triangle. could you add a picture of the triangle so i can help?

Step-by-step explanation:

You might be interested in

Which of the followibg expressions is equivalent to the expression a^2/3

Naily [24]

Answer:

C. I can’t really enter square roots

Step-by-step explanation:

a^2/3 = a^2*a^1/3

Which is the cube root of a squared

4 0

3 years ago

Determine the slope and y intercept. Y=3/2x+3

Harlamova29_29 [7]

Slope: 3/2 (the coefficient of x)

Y-Intercept: (0,3) (substituting x = 0 into the equation)

Ans: Yellow

7 0

3 years ago

Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).

lutik1710 [3]

Answer:

The arc length is $\dfrac{21}{16}$

Step-by-step explanation:

Given that,

The given curve between the specified points is

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

The points from $(\dfrac{9}{16},1)$ to $(\dfrac{9}{8},2)$

We need to calculate the value of $\dfrac{dx}{dy}$

Using given equation

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

On differentiating w.r.to y

$\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})$

$\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}$

We need to calculate the arc length

Using formula of arc length

$L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}$

Put the value into the formula

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}$

$L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}$

$L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}$

$L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}$

Put the limits

$L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})$

$L=\dfrac{21}{16}$

Hence, The arc length is $\dfrac{21}{16}$

6 0

3 years ago

Kathleen makes bracelets to sell in a booth at a local store. She spent $62.30 on supplies to make bracelets for the next month.

vodomira [7]

Answer:

$105.20

Step-by-step explanation:

Given that :

Cost of materials = $62.30

Cost of booth = $25 / month

Price per bracelet = $5.50

Profit of 35 bracelet is sold next month =?

Profit = Revenue - Expenses

Revenue = $5.50 * 35 = $192.50

Expenses = $25 + $62.30 = $87.30

Profit = $192.50 - $87.30

= $105.20

4 0

3 years ago

The expression below is a factorization of what trimonial (5x+6)(3x-2)

STatiana [176]

Answer:

$15x^2 + 8x -12$

Step-by-step explanation:

(5x+6)(3x-2)

"foil" it out

F: 5x * 3x = 15x^2

O: 5x * -2 = -10x

I: 6*3x = 18x

L: 6 * -2 = -12

3 0

3 years ago

Read 2 more answers