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NemiM [27]
2 years ago
5

Which of the following is the graph of the quadratic function y=x^2 - 4x + 4?

Mathematics
2 answers:
Dennis_Churaev [7]2 years ago
8 0

Answer:

look at x=0 and plug in 0 for any x you find in the equation

f(0) = 0² - 4*0 +4 = 4

c is out of the race then

let's do this again, but test for x=1 and x=2

f(1) = 1² - 4*1 + 4 = 1

f(2) = 2² - 4*2 +4 = 0

a and b are out

its graph d

when testing like this, choose easy-to-calculate numbers to find out what points you get when asking for the y-value at an arbitrary x-place

nordsb [41]2 years ago
7 0

Answer:

D

Step-by-step explanation:

convert into vertex form

x^2-4x+4 = (x-2)^2 +0

vertex: (2, 0)

Graph D has vertex (2, 0)

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I need a better explanation how to find length and area of a triangle
fomenos

Answer:

Height(h) = 24in

Area = 204in²

Step-by-step explanation:

we would use the heron formula because we have all the sides to calulate the area

S  = (A+B+C)/2 = (25 + 17 + 26)/2 = 68/2 = 34

area = √s(s-a)(s-b)(s-c)  = √34(34-25)(34-17)(34-26) = √34(9)(17)(8) = √34x9x17x8 = √41616 = 204

area= (1/2)bh

    204 = (1/2)bh b= 17, h =?

204 = (1/2)17h

204 x 2 = 17h

408 = 17h

h = 408/17 = 24in

Height(h) = 24in

Area = 204in²

4 0
3 years ago
to find the area of a trapezoid dylan uses the formula A=1/2 (B1+B2)h the bases have lengths of 3.6 cm and 12 1/3 cm. the height
Artemon [7]

Answer:

It is irrational because it can not be represented as a fraction of two integers

Step-by-step explanation:

Given

B_1 = 3.6

B_2 = 12\frac{1}{3}

H = \sqrt[3]5

Required

Why is the area irrational?

First, we need to calculate the area

Area = \frac{1}{2}(B_1 + B_2) * H

Area = \frac{1}{2}(3.6 + 12\frac{1}{3}) * \sqrt[3]5

Area = \frac{1}{2}(3.6 + \frac{37}{3}) * 17100

Area = \frac{1}{2}(\frac{10.8+37}{3}) * 1.710

Area = \frac{1}{2}(\frac{47.8}{3}) * 1.7100

Area = \frac{47.8}{6} * 1.7100

Area = \frac{47.8* 1.7100}{6}

Area = \frac{81.738}{6}

Area = 13.623

<em>It is irrational because it can not be represented as a fraction of two integers</em>

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