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Allisa [31]
3 years ago
13

Jim Rome is making prizes for a game at school Fair he has two bags of different pins one with 15 pins and one with 20 pins ever

y prize will have one kind of pain and will have the greatest number of pins possible how many pens should be in each prize
Mathematics
1 answer:
ohaa [14]3 years ago
8 0
 You have to find the greatest common factor of the two numbers 15 and 20. The greatest common factor is 5, so Jerome can give out 5 pieces of candy as a prize from each bag; three prizes from the bag of 15 and 4 prizes from the bag of 20.<span>
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The number of sit-ups that all tenth-grade girls can do in 5 minutes is normally distributed. beth surveyed 20 of her fellow int
Luda [366]

The true statement is as follows "No because she did not use a simple random sample".

<h3>What is random sampling?</h3>

Random sampling is the method to choose the given samples of observation to make assumptions about the population.

It is given that

Population: All tenth-grade girls

Sample: 20 intramural tennis players

The 20 intramural tennis players cannot represent all tenth-grade girls.

This is so because the selection is biased here, and it could not be used to make inferences about the overall population. then she did not use a simple random sample.

Hence, the true statement is (b)

Read more about random sampling at:

brainly.com/question/1334729

5 0
3 years ago
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Planners of an experiment are evaluating the design of a sphere of radius r that is to be filled with helium (0°c, 1 atm pressur
Vikentia [17]
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3 
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3 
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3) 
The density of silver is 10.5g/cm^3 
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2) 

Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3 

Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2) 
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
6 0
4 years ago
Dave Flip a coin 20 times and got heads on eight of the flips Based on Dave's results what is the experimental probability of th
Elodia [21]
Four tenths, .4 or 8/20
8 0
3 years ago
True or false:<br> the following equation is in standard form. <br> (x - 4.2)^2 - 3 = 0
natita [175]

Answer:

false

Step-by-step explanation:

standard form cannot contain fractions or decimals

3 0
3 years ago
When Zack checked his solution, it didn’t work. What was his mistake?
KatRina [158]

Answer:

he whent up and not down and left and not right

Step-by-step explanation:we just is messed up in life

4 0
3 years ago
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