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Allisa [31]
3 years ago
13

Jim Rome is making prizes for a game at school Fair he has two bags of different pins one with 15 pins and one with 20 pins ever

y prize will have one kind of pain and will have the greatest number of pins possible how many pens should be in each prize
Mathematics
1 answer:
ohaa [14]3 years ago
8 0
 You have to find the greatest common factor of the two numbers 15 and 20. The greatest common factor is 5, so Jerome can give out 5 pieces of candy as a prize from each bag; three prizes from the bag of 15 and 4 prizes from the bag of 20.<span>
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What is 13÷1/3 converted to decimal form
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PLEASE HELP! I will give you the brainiest and A LOT of points!
LiRa [457]

Answer:

Company B pays more!

Step-by-step explanation:

All you have to do is...

25,000x10=250,000

+

1,600x10=16,000

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28,500x10=285,000

+

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umka21 [38]

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6 0
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Lyrx [107]
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8 0
3 years ago
(2 5/8 + 5/6 + 1 1/8
VLD [36.1K]
<h2>2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8} = 3\dfrac{19}{12}  or, \dfrac{55}{12}</h2>

Step-by-step explanation:

We have,

2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8}

To find, the value of 2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8} = ?

∴ 2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8}

= 2+\dfrac{5}{8}+\dfrac{5}{6}+1+\dfrac{1}{8}

= (2+1)+(\dfrac{5}{8}+\dfrac{5}{6}+\dfrac{1}{8})

= 3 + \dfrac{15+20+3}{24}

= 3 + \dfrac{19}{12}

= 3\dfrac{19}{12}  or, \dfrac{55}{12}

∴ 2\dfrac{5}{8}+\dfrac{5}{6}+1\dfrac{1}{8} = 3\dfrac{19}{12}  or, \dfrac{55}{12}

6 0
3 years ago
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