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statuscvo [17]
3 years ago
7

What is the answer? [(12 − 5) • 12] ÷ 6

Mathematics
2 answers:
Sever21 [200]3 years ago
6 0
(7 × 12 )/ 6
= 7×2
= 14
tatiyna3 years ago
6 0
14 is the correct answer to this question
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Help me on this question please​
Luba_88 [7]
Sorry hun I’ve never learned that
5 0
2 years ago
Write an equation of the circle with center (4,5) and radius 9.
mixer [17]

Answer:

I'm going to write both of these because maybe you have a fill in the blank question. I don't know.

(x-4)^2+(y-5)^2=9^2

Simplify:

(x-4)^2+(y-5)^2=81

Step-by-step explanation:

(x-h)^2+(y-k)^2=r^2 is the equation of a circle with center (h,k) and radius r.

You are given (h,k)=(4,5) because that is the center.

You are given r=9 because it says radius 9.

Let's plug this in.

(x-4)^2+(y-5)^2=9^2

Simplify:

(x-4)^2+(y-5)^2=81

6 0
3 years ago
Read 2 more answers
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is \frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}.

Now we will solve this expression with the help of law of exponents.

\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}

           =\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}

           =2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}

           =2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}

           =2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}

           =2^{\frac{2}{9}}\times 3^{-\frac{2}{3} } [Option 2]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2 [Option 1]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2

                =(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }

                =\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} } [Option 3]

2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }

               =\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}} [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0
2 years ago
You start hiking at an elevation that is 80 meters below base camp.
Arte-miy333 [17]

Answer:

You are now 38 m below base camp.

Step-by-step explanation:

Consider the provided information.

You start hiking at an elevation that is 80 meters below base camp.

Now your initial location is 80 m below base camp, that can be represents as: -80

Now you increase your elevation by 42.

So you go up by 42.

In other words, you get the equation -80+42 = -38.

Since a negative value is below the base camp, this means that you are now 38 m below base camp.

6 0
3 years ago
Help pls i am not sure what to do
stiv31 [10]
Number 49 is Acute .
4 0
3 years ago
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