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2 years ago

9

Sarah bought 6 2/3 yards of material. She used 3/4 of the material to make a costume for the school play. How much material did

she have left after making the costume? *

1 answer:

Lelechka [254]2 years ago

7 0

You’re full of cap don’t cap next time you’re capping the answer is 5/3

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If a card is chosen at random from a pack of 52 playing cards, what is the probability of a Queen or a Club?

bonufazy [111]

The answer is b because you have 4 queens in a deck of cards and 13 clubs in a deck so if you add them you would get 17/52 cards

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2 years ago

What value of p makes the equation true?

steposvetlana [31]

Answer:

Step-by-step explanation:

1/2

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3 years ago

Read 2 more answers

I need help with this I will mark you if right

kodGreya [7K]

I’m pretty sure it’s c

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2 years ago

An article claims that 12% of trees are infested by a bark beetle. A random sample of 1,000 trees were tested for traces of the

inna [77]

Answer: 0.6812

Step-by-step explanation:

Let p be the population proportion of trees are infested by a bark beetle.

As per given: p= 12%= 0.12

Sample size : n= 1000

Number of trees affected in sample = 1000

Sample proportion of trees are infested by a bark beetle. = $\hat{p}=\dfrac{127}{1000}=0.127$

Now, the z-test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

So, $z=\dfrac{0.127-0.12}{\sqrt{\dfrac{0.12\times 0.88}{1000}}}$

$z=\dfrac{0.007}{\sqrt{\dfrac{0.1056}{1000}}}\\\\\\=\dfrac{0.007}{\sqrt{0.0001056}}\\\\\\=\dfrac{0.007}{0.010276}\approx0.6812$

Hence, the value of the z-test statistic = 0.6812 .

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3 years ago

What is the solution to the system of equations?

Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}$

$\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}$

$x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10$

4 0

2 years ago