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Viktor [21]
3 years ago
11

Solve the equations 3x+2y=5 and 3x-2y=1 by elimination method.​

Mathematics
2 answers:
alexira [117]3 years ago
6 0

Answer:

x = 1

y = 1

Step-by-step explanation:

3x + 2y = 5

3x - 2y = 1 (subtract these equations)

––––––––––––

4y = 4

divide by two

y = 1

input y = 1 the other equations

3x + 2 = 5

simplify

3x = 3

x = 1

Stells [14]3 years ago
6 0

Answer:

3x+2y=5.......(1)

3x-2y=1.........(2)

subtracting equation 1 by 2

3x+2y=5

3x-2y=1.

- +. =-

_________

3x-3y+2y-(-2y)=5-1

2y+2y=4

4y=4

y=4/4=1answer

adding equation 1 &2 we get

3x+2y=5

3x-2y=1

+

________

3x+3x+2y-2y=5+1

6x=6

x=6/6=1

:.x=1&y=1

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8(y+4)-2(y-1)=70-3y help pls
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Answer:

y = 4

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8(y+4)-2(y-1)=70-3y

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One root of the quadratic equation x^2 − 2x + m = 0 is 9. If the other root is n, what is n−m?
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4 0
3 years ago
Solve the equation |x-2|-3=0 first by finding the zeros of<br> y=|x-2|-3 and then algebraically.
tino4ka555 [31]

Answer:

The solution of given equation are -1 and 5.

Step-by-step explanation:

The given equation is

|x-2|-3=0

We need to solve the above equation by finding the zeros of

y=|x-2|-3

The vertex form of an absolute function is

y=a|x-h|+k

where, a is constant and (h,k) is vertex.

Here, h=2, k=-3. So vertex of the function is (2,-3).

The table of values is

   x           y

   0         -1

   2         -3

   4         -1

Plot these points on a coordinate plane and draw a V-shaped curve with vertex at (2,-3).

From the given graph it is clear that the graph intersect x-axis at -1 and 5. So, zeroes of the function y=|x-2|-3 are -1 and 5.

Therefore the solution of given equation are -1 and 5.

Now solve the given equation algebraically.

|x-2|-3=0

Add 3 on both sides.

|x-2|=3

x-2=\pm 3

Add 2 on both sides.

x=\pm 3+2

x=3+2 and x=-3+2

x=5 and x=-1

Therefore the solution of given equation are -1 and 5.

3 0
4 years ago
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