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Iteru [2.4K]
2 years ago
10

Ill give brainliest Triangle Sum Theorem CLASSWORK

Mathematics
2 answers:
olasank [31]2 years ago
8 0

Answer:

(14x + 1) + 90 + 61 = 180 \\ 14x + 152 = 180 \\ 14x = 28 \\  \boxed{x = 2}

<h3>2 is the right answer.</h3>

(4x + 3) + 55 + 70 = 180 \\ 4x + 128 = 180 \\ 4x = 52 \\  \boxed{x = 13}

<h3>13 is the right answer.</h3>

zepelin [54]2 years ago
7 0

Step-by-step explanation:

Sum of angles in a triangle = 180°.

Question 3:

We have 90° + 61° + (14x + 1)° = 180°.

=> 14x° + 152° = 180°

=> 14x° = 28°

=> x = 2.

Question 4:

We have 70° + 55° + (4x + 3)° = 180°.

=> 4x° + 128° = 180°

=> 4x° = 52°

=> x = 13.

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Write the equation of the circle with center (5, 1) and radius r = 10
kherson [118]
The standard equation for the circle is:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle and r is the radius.

We are given that the center is (5,1) and r=10 so

(x-5)^2+(y-1)^2=100
4 0
3 years ago
TIVITY MODULE
bezimeni [28]

Answer: Length: 4, width: 6

Step-by-step explanation:

Let the length be x and width be y

Then x=2y-8 and xy=24

Substitute to get 2y-8 * y = 24, so 2y^2-8y=24 or y^2-4y=12, then solve to get y=6 or y=-2. Since width is positive y=6.

Substitute y=6 into xy=24 to get x=4.

Length: 4, width: 6

Hope that helped,

-sirswagger21

6 0
3 years ago
What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE
maks197457 [2]

Given:

The equation of a line is:

2y+3x=10

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

2y+3x=10

For x=0,

2y+3(0)=10

2y+0=10

y=\dfrac{10}{2}

y=5

For x=2,

2y+3(2)=10

2y+6=10

2y=10-6

2y=4

Divide both sides by 2.

y=\dfrac{4}{2}

y=2

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

(x,y)\to (3x,3y)

Using this rule, we get

A(0,5)\to A'(3(0),3(5))

A(0,5)\to A'(0,15)

Similarly,

B(2,2)\to B'(3(2),3(2))

B(2,2)\to B'(6,6)

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-15=\dfrac{6-15}{6-0}(x-0)

y-15=\dfrac{-9}{6}(x)

y-15=\dfrac{-3}{2}x

Multiply both sides by 2.

2(y-15)=-3x

2y-30=-3x

2y+3x=30

Therefore, the equation of the line after the dilation is 2y+3x=30.

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